x+y=10
x-y=8, x=y+8
y+8+y=10
2y=2
y=1
So, x=10-y=10-1=9.
Numbers Would be 9 and 1.
To find where on the hill the canonball lands
So 0.15x = 2 + 0.12x - 0.002x^2
Taking the LHS expression to the right and rearranging we have -0.002x^2 + 0.12x -
0.15x + 2 = 0.
So we have -0.002x^2 - 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x^2 + 0.03x -2 = 0.
This is a quadratic eqn with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25. The second solution y = 0.15 * 25 = 3.75
Answer:
1/4.
Step-by-step explanation:
That is 1 - (1/4 + 2/5 + 1/10).
The Lowest common multiple 4 5 and 10 is 20 so we have
20/20 - (5/20 + 8/20 + 2/20)
= 20/20 - 15/20
= 5/20
= 1/4 answer.
The answer’s c, y=5/2x+10
Answer:
A rhombus is quadrilateral with all side of equal length. Thus a quadrilateral with all sides of equal length and all angles right angles is still a rhombus but it is also a square. It is also a quadrilateral, a rectangle and a parallelogram.
Step-by-step explanation:
I hope this helped! have a great day! :)
