Need this geometry answer quick!(I think its answer c but not sure)

Mathematics

1 answer:

Vsevolod [243]4 years ago

7 0

180 is the answer....

angle B =50
angle C = 130

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Simplify (5x^-6)^3 leave your answer as a fraction in index form

Elan Coil [88]

Answer: 125/x^18

Step-by-step explanation: this should be the answer

5 0

3 years ago

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Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$

Anna [14]

Answer:

$\large\boxed{1\dfrac{1}{3}\ u^2}$

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

$x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1$

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

$\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}$

6 0

3 years ago

HELPPP ME PLSSSS!!!!!!!!!!!!!!!!!!!!!!!1 I BEGGGG

NeX [460]

The answer is A Ezra is right

5 0

3 years ago

Help me i will give you 50 points

jeyben [28]

1) (f + g)(2) = 7 + 3 = 10 The answer is C

2) (f - g)(4) = 11 - 15 = -4 The answer is A

3) f(1) = 2(1) + 3 = 5 g(1) = 1² - 1 = 0 The answer is D

4) (f xg ) (1) = 7/3 The answer is B

5 0

3 years ago

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The length of a concrete slab is three more than three times the width. It's area is 330 square feet. What is the length of the

marin [14]

Answer:

Width: 10.5 feet

Length: 31.5 feet

Step-by-step explanation:

Let x represent width of the concrete slab.

We have been given that the length of a concrete slab is three more than three times the width. So length of the slab would be $3x$ .