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3 years ago

PLEASE HELP ASAP ASAP ASAP ASAP ASAPA ASAP

Mathematics

2 answers:

Shkiper50 [21]3 years ago

7 0

5/3=1.6666 hope this helpssssssssssssssssssss

Shalnov [3]3 years ago

7 0

Answer:

Step-by-step explanation:

The box at the top left is 1

The box under 5 is 3

The box at the bottom is 2

The box on the top right is 2

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3 years ago

PLEASE HELP! Find an equation of the line whose intercepts are twice those of the graph of 5y+2x=10.

valina [46]

5y+2x=10y=−25x+2246810−2−4−6−8−10246810−2−4−6−8−10Let's solve for x.5y+2x=10Step 1: Add -5y to both sides.2x+5y+−5y=10+−5y2x=−5y+10Step 2: Divide both sides by 2.2x2=−5y+102x=−52y+5Answer:x=−52y+5

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3 years ago

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Which graph represents an exponential function?

Maksim231197 [3]

Answer:

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Step-by-step explanation:

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3 years ago

When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected

jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

$N=\frac{12.36}{0.03+0.55^t}$

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

$N=\frac{12.36}{0.33+0.55^0}$

$N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12$

A. Initially, there were 12 deer.

B. $N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380$

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. $N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410$

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

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3 years ago

A company has two manufacturing plants with daily production levels of 5x +14 items and 3x-7 items, respectively. The first pla

Llana [10]

Answer:

The first plant produces 2x + 21 more items daily than the second plant.

Step-by-step explanation:

The daily production of the two plants are:

Plant 1: 5x + 14

Plant 2: 3x - 7

Compute the number of items first plant produces more than the second plant as follows:

$\text{Plant 1 - Plant 2}=5x+14-3x+7\\\\=2x+21$

Thus, the first plant produces 2x + 21 more items daily than the second plant.

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