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lys-0071 [83]
3 years ago
5

How would you solve this linear system?

Mathematics
1 answer:
Hoochie [10]3 years ago
8 0

(x, y ) = (- 6, 3 )

Since both equations express y in terms of x, we can equate them

2x + 15 = - \frac{1}{3} x + 1

( add \frac{1}{3} x to both sides )

\frac{7}{3} x + 15 = 1 ( subtract 15 from both sides )

\frac{7}{3} x = - 14

( multiply both sides by 3 and divide by 7 )

x = ( 3 × - 14 )/7 = - 6

substitute x = - 6 into either of the 2 equations for y- coordinate )

y = ( 2 × - 6 ) + 15 = 3

solution : (x, y ) = ( - 6, 3 )


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Step-by-step explanation:

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