So, this is too vague but I'll solve for both quadratic formula and find the discriminant.
Quadratic formula: <span>x=<span>5+<span><span><span>√35 OR</span><span> </span></span>x</span></span></span>=<span>5−<span>√<span>35
Finding the discriminant: 141</span></span></span>
Answer:
I think these are the right answers. The answer to one is 32. The answer to two is 38.
1: 2[18-(5+3^2)/7]
2[18-(5+9)/7]
2[18-14/7]
2[18-2]
2 times 16 = 32
2: I used a calculator for this one.
Solve:
"<span>twice the number minus three times the reciprocal of the number is equal to 1."
3(1)
Let the number be n. Then 2n - ------- = 1
n
Mult all 3 terms by n to elim. the fractions:
2n^2 - 3 = n. Rearranging this, we get 2n^2 - n - 3 = 0.
We need to find the roots (zeros or solutions) of this quadratic equation.
Here a=2, b= -1 and c= -3. Let's find the discriminant b^2-4ac first:
disc. = (-1)^2 - 4(2)(-3) = 1 + 24 = 25.
That's good, because 25 is a perfect square.
-(-1) plus or minus 5 1 plus or minus 5
Then x = ------------------------------ = --------------------------
2(2) 4
x could be 6/4 = 3/2, or -5/4.
You must check both answers in the original equation. If the equation is true for one or the other or for both, then you have found one or more solutions.</span>
change the mixed numbers to improper fractions and multiply the numerators / denominators
10 
= 
× = = 1110 
The lengths of the rectangles are 7 and 12 respectively. Form the ratio 7/12. The widths of the rects. are x and 5 respectively. Form the ratio x/5. Now equate these two ratios:
7 x
--- = ---
12 5
Solve this for x. One way to do this would be to cross-multiply, obtaining 12x = 35, and solving this result for x. x will be a fraction. Write the numerator and denominator in the boxes given.
