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777dan777 [17]
3 years ago
8

Justin bought 6 ribbons for an project . Each ribbons is 1/4 yard long . How many yards of ribbons did Justin buy?

Mathematics
2 answers:
Aliun [14]3 years ago
7 0
If you need to simplify your answer to a mixed number, your answer would actually be 1 1/2

( 6/4 = 1 2/4 = 1 1/2)
d1i1m1o1n [39]3 years ago
3 0
6 ribbons 
1/4 yard long each 
4 yards= 4 ribbons 
4/4 yards 
A: 6/4 Yards
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I NEED HELP LOTS OF HELP!!!
Crazy boy [7]

Answer:

Step-by-step explanation:

the answer to number 7 is 1953152

3 0
3 years ago
Can someone also explain how to get the answer thank u
goblinko [34]

Answer:

m = -\frac{194}{3}

Step-by-step explanation:

I'm assuming you are trying to find m. In order to do so, you need to get m on one side.

Before doing that let's multiple -2 and -3m by \frac{4}{3}

256=-\frac{8}{3} - 4m

add -\frac{8}{3} to both sides

258\frac{2}{3}=-4m

I would get rid of the fraction so I'd multiply both sides by \frac{3}{1}

\frac{776}{3}*3 = 4m*3

776=-12m

divide both sides by -12m

m = -\frac{776}{12}

which can be simplified to

m = -\frac{194}{3}

ALL UNLESS THAT \frac{4}{3} IS A POWER

3 0
2 years ago
97.2
makvit [3.9K]

Answer:

Step-by-step explanation:

x = 774.37(0.972)

x = 752.68764

x = 752.69  km

descending order???? OK... 97652

4 0
2 years ago
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 11z on the curve of intersection of the plane x − y + z =
Taya2010 [7]

Answer:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

<em>Maximum value of f=2.41</em>

Step-by-step explanation:

<u>Lagrange Multipliers</u>

It's a method to optimize (maximize or minimize) functions of more than one variable subject to equality restrictions.

Given a function of three variables f(x,y,z) and a restriction in the form of an equality g(x,y,z)=0, then we are interested in finding the values of x,y,z where both gradients are parallel, i.e.

\bigtriangledown  f=\lambda \bigtriangledown  g

for some scalar \lambda called the Lagrange multiplier.

For more than one restriction, say g(x,y,z)=0 and h(x,y,z)=0, the Lagrange condition is

\bigtriangledown  f=\lambda \bigtriangledown  g+\mu \bigtriangledown  h

The gradient of f is

\bigtriangledown  f=

Considering each variable as independent we have three equations right from the Lagrange condition, plus one for each restriction, to form a 5x5 system of equations in x,y,z,\lambda,\mu.

We have

f(x, y, z) = x + 2y + 11z\\g(x, y, z) = x - y + z -1=0\\h(x, y, z) = x^2 + y^2 -1= 0

Let's compute the partial derivatives

f_x=1\ ,f_y=2\ ,f_z=11\ \\g_x=1\ ,g_y=-1\ ,g_z=1\\h_x=2x\ ,h_y=2y\ ,h_z=0

The Lagrange condition leads to

1=\lambda (1)+\mu (2x)\\2=\lambda (-1)+\mu (2y)\\11=\lambda (1)+\mu (0)

Operating and simplifying

1=\lambda+2x\mu\\2=-\lambda +2y\mu \\\lambda=11

Replacing the value of \lambda in the two first equations, we get

1=11+2x\mu\\2=-11 +2y\mu

From the first equation

\displaystyle 2\mu=\frac{-10}{x}

Replacing into the second

\displaystyle 13=y\frac{-10}{x}

Or, equivalently

13x=-10y

Squaring

169x^2=100y^2

To solve, we use the restriction h

x^2 + y^2 = 1

Multiplying by 100

100x^2 + 100y^2 = 100

Replacing the above condition

100x^2 + 169x^2 = 100

Solving for x

\displaystyle x=\pm \frac{10}{\sqrt{269}}

We compute the values of y by solving

13x=-10y

\displaystyle y=-\frac{13x}{10}

For

\displaystyle x= \frac{10}{\sqrt{269}}

\displaystyle y= -\frac{13}{\sqrt{269}}

And for

\displaystyle x= -\frac{10}{\sqrt{269}}

\displaystyle y= \frac{13}{\sqrt{269}}

Finally, we get z using the other restriction

x - y + z = 1

Or:

z = 1-x+y

The first solution yields to

\displaystyle z = 1-\frac{10}{\sqrt{269}}-\frac{13}{\sqrt{269}}

\displaystyle z = \frac{-23\sqrt{269}+269}{269}

And the second solution gives us

\displaystyle z = 1+\frac{10}{\sqrt{269}}+\frac{13}{\sqrt{269}}

\displaystyle z = \frac{23\sqrt{269}+269}{269}

Complete first solution:

\displaystyle x= \frac{10}{\sqrt{269}}\\\\\displaystyle y= -\frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{-23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=-0.4

Complete second solution:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=2.4

The second solution maximizes f to 2.4

5 0
3 years ago
If you help I will give you brainliest
hammer [34]

9514 1404 393

Answer:

  5 miles

Step-by-step explanation:

Time/speed/distance problems can be worked a number of ways. Here, we want to know the distance walked. We know the total time and the total distance and the two different speeds. So, we can use a variable to represent the value we want to know: w = distance walked (in miles).

The total time is 9:00 -6:50 = 2:10 = 2 1/6 hours = 13/6 hours.

The total time is the sum of times for the two parts of the trip: walking and riding.

  walking time = walking distance/walking speed

  = w/3

  riding time = riding distance/riding speed

  = (20-w)/30

The total time is that given above:

  w/3 +(20-w)/30 = 13/6

  10w +(20 -w) = 65 . . . . . . . . multiply by 30

  9w = 45 . . . . . . . . . . . . subtract 20, collect terms

  w = 5 . . . . . . . . . . . divide by 9

The girl walked 5 miles.

8 0
3 years ago
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