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3 years ago

Why can a problem with extra information be difficult to solve?

2 answers:

5 0

A problem with extra information will be difficult to solve because you may not be able to tell what information you might need to use for the problem.

slega [8]3 years ago

4 0

Because you have more to look at and it can confuse some people

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Pls answer the question below!

frutty [35]

Answer:

fgffdssSsdddsdddddffffffffggfffg

8 0

3 years ago

Read 2 more answers

Find the sum of the first five terms using the geometric series formula for the sequence left curly bracket 1 half comma space m

MatroZZZ [7]

Answer:

$\bold{\dfrac{11}{2 }}$

Step-by-step explanation:

Given the geometric series:

$\{\dfrac{1}2, -1, 2, -4, ..... \}$

To find:

Sum of series upto 5 terms using the geometric series formula = ?

Solution:

Formula for sum of a n terms of a geometric series is given as:

$S_n=\dfrac{a(1-r^n)}{1-r} \ \{r$

$a$ is the first term of the geometric series

$r$ is the common ratio between each term (2nd term divided by 1st term or 3rd term divided by 2nd term ..... ).

Here:

$a = \dfrac{1}{2}$

$r = \dfrac{-1}{\dfrac{1}{2}} = -2$

$n=5$

So, applying the formula for given values:

$S_5=\dfrac{\dfrac{1}2(1-(-2)^5)}{1-(-2)} \\\Rightarrow S_5=\dfrac{1-(-32)}{2 \times 3} \\\Rightarrow S_5=\dfrac{1+32}{6} \\\Rightarrow S_5=\dfrac{33}{6} \\\Rightarrow \bold{S_5=\dfrac{11}{2}}$

So, the answer is

$\bold{\dfrac{11}{2 }}$

3 0

4 years ago

I need help.....plz. hopefully u can solve the problem but i need the answer asp

GuDViN [60]

Answer:

I believe the answer would be 4 :) hope this helps

4 0

3 years ago

Read 2 more answers

Eighty percent of all California drivers wear seat belts. If three drivers are pulled over,

romanna [79]

Answer:

The probability that the three drivers would wear seat belts is 0.5

Step-by-step explanation:

Given

Percentage of drivers using seat belt = 80%

Number of drivers pulled over = 3

Required

Probability that all three drivers wore seat belt

First, the probability that a driver would wear seat belt has to be calculated.

Let's represent that with P(D)

P(D) is equivalent to the percentage of drivers using seat belt

$P(D) = 80%$ %

$P(D) = \frac{80}{100}$

$P(D) = 0.8$

Let the probability that the three drivers would wear seat belts be represented as P(All).

P(All) is calculated as thus;

(Probability that the first driver would wear seat belt) and (Probability that the second driver would wear seat belt) and (Probability that the first driver would wear seat belt).

Mathematically, this means

$P(All) = P(D) * P(D) * P(D)$