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3 years ago

5

A builder planned to build dog houses for his pets .each dog house will be on 1/3 of an acre of land .how much land will he need

for 6 dog houses

1 answer:

ryzh [129]3 years ago

5 0

You will need 1/2 of an acre

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Prove that sin20sin40sin60sin80=3/16

never [62]

We'll use the following properties of sine and cosine to prove this:

$sin(a)\cdot sin(b) = \frac12(cos(a-b) - cos(a+b))$

$cos(a)\cdot cos(b) = \frac12(cos(a+b) + cos(a-b))$

$cos(180+a) = cos(180-a)$

Then it's just a matter of filling it in...

sin20sin40 * sin60sin80 = 1/2(cos20 - cos60) * 1/2 (cos20 - cos140) =

1/8( cos40 + 1 - cos160 - cos120 - cos40 - cos80 + cos80 + cos200) =

1/8(1 - cos160 - cos120 + cos200) =

1/8(1 - cos160 - cos120 + cos160) =

1/8(1 - cos120 ) = 1/8( 1 + 1/2 ) = 3/16

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dolphi86 [110]

9 10th of the cap is sewn because you multiply 5 times two to get them b
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Find the 64th term of the following arithmetic sequence.<br> 6, 14, 22, 30,

olga55 [171]

Answer:

<h2>510</h2><h2 />

Step-by-step explanation:

30-22=8

22-14=8

14-6=8

then

→ the common difference r = 8

→ the first term = 6

THerefore, (accoriding to the standard explicit formula)

the 64th term = term 1 + (64 - 1)×r

= 6 + 63×8

= 510

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3 years ago