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oksian1 [2.3K]
3 years ago
13

Which polygon appears to be regular?

Mathematics
1 answer:
ivolga24 [154]3 years ago
5 0

Answer:

  Figure A

Step-by-step explanation:

A regular polygon has all sides the same length and all angles the same measure. Only Figure A matches that description.

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
What is a gradient of a line
Dennis_Churaev [7]
(slope) The higher the gradient<span> of a graph at a point, the steeper the </span>line<span> is at that point.</span>
4 0
3 years ago
Read 2 more answers
Diana is painting statues. She has \dfrac{7}{8} 8 7 ​ start fraction, 7, divided by, 8, end fraction of a liter of paint remaini
anzhelika [568]

Answer:

Number of statues that can be painted are 17

Step-by-step explanation:

Initially Diana has \frac{7}{8} liters of paint remaining.

Every statue requires \frac{1}{20} liters of paint for painting.

We have to find how many statues we will be able to paint with this remaining paint.

To get the number of statues,

Number of statues = \frac{Paint remaining}{Paint required for 1 statue}

number of statues = \frac{\frac{7}{8} }{\frac{1}{20} }

                               = \frac{35}{2} = 17.5

Since the number of statues is not an integer the maximum number of statues that can be painted are 17.

3 0
3 years ago
Read 2 more answers
Compute the lower Riemann sum for the given function f(x)=x2 over the interval x∈[−1,1] with respect to the partition P=[−1,− 1
Nata [24]

Answer:

21/64

Step-by-step explanation:

First, we need to note that the function f(x) = x² is increasing on (0, +∞), and it is decreasing on (-∞,0)

The first interval generated by the partition is [-1, -1/2], since f is decreasing for negative values, we have that f takes its minimum values at the right extreme of the interval, hence -1/2.

The second interval is [-1/2, 1/2]. Here f takes its minimum value at 0, because f(0) = 0, and f is positive otherwise.

Since f is increasing for positive values of x, then, on the remaining 2 intervals, f takes its minimum value at their respective left extremes, in other words, 1/2 and 3/4 respectively.

We obtain the lower Riemman sum by multiplying this values evaluated in f by the lenght of their respective intervals and summing the results, thus

LP(f) = f(-1/2) * ((-1/2) - (-1)) + f(0) * (1/2 - (-1/2)) + f(1/2)* (3/4 - 1/2) + f(3/4) * (1- 3/4)

= 1/4 * 1/2 + 0 * 1 + 1/4 * 1/4 + 9/16 * 1/4 = 1/8 + 0 + 1/16 + 9/64 = 21/64

As a result, the lower Riemann sum on the partition P is 21/64

3 0
3 years ago
Helpgchjsghjcvbxnvbsvjdgasghgbhdvbahgvgbd
maxonik [38]

Answer:

yeah it's blurry ¯\_(ツ)_/¯

8 0
3 years ago
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