Answer:
Step-by-step explanation:
If 5! is equal to 5 × 4 × 3 × 2 × 1 and 6! is equal to 6 × 5 × 4 × 3 × 2 × 1, then 4! is equal to 4 × 3 × 2 × 1. Thus, 4! = 4 × 3 × 2 × 1, which can simplify to 24. 4! = 24.
is basically 4 × 4 × 4 × 4, which can simplify to 256.
So, 
= 
. can simplify to . Therefore, = .
Answer:
aₙ = -15 + 10 * (n-1)
Step-by-step explanation:
aₙ = a₁ + (n-1)*d a₁: first term d: common difference
a₅ a₁ + 4d =25 .... (1)
a₁₁ a₁ + 10d = 85 ...(2)
(2) - (1) 6d = 60
d = 10
a₁ = -15
Formula: aₙ = -15 + 10 * (n-1)
So to solve this question, your goal is to find out how the way it is solved is not correct.
Your answer would be: On the third line, the student adds the 8 to both sides instead of subtracting. The way the initial equation is given is
y-(-8)=-6(x-2). After distributing the six, the student should make the 8 positive because subtracting a negative makes a positive. After solving, the equation should look like: y(+8)=-6x+12, so you would subtract the 8 from both sides instead of adding it, and solve from there.
(-36x^4y+144x²y^6) / (-4x²y) =
36xy*(x³+4xy^5) / (-4x²y) =
-9*(x³+4xy^5) / x
Answer:
sorry getting points
Step-by-step explanation:
