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4 years ago

Can you estimate 7533

1 answer:

7 0

Based on your comment I assume you want to find 7,533 subtracted by 7,200. To estimate this, round 7,533 to the hundreds place, so 7,533 becomes 7,500.

7,500 - 7,200 = 300, using mental math.

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108 cookies in 36 minutes. how many cookies did he decorate per minute?

Mumz [18]

Answer:

Step-by-step explanation:

108 divided by 36 = 3

search up 108 / 36

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3 years ago

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The Edwards family's bill for dinner is 42.95 how much should they tip their server assuming they tip the normal 15%

gladu [14]

They should tipp 6,44

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3 years ago

Help me out with this one guys <br> (10 points)

Anna007 [38]

M is 3 and -3

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3 years ago

The exponential distribution applies to lifetimes of a certain component. Its failure rate is unknown. Find the probability that

wlad13 [49]

Answer:

a) 0.0821

b) 0.0111

c) 0.0041

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \lambda e^{-\lambda x}$

In which $\lambda$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\lambda x}$

Either it lasts more 5 years or less, or it survives more than 5 years. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 5) + P(X > 5) = 1$

In all 3 cases, we want P(X > 5). So

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = 1 - e^{-5\lambda}$

(a) lambda=.5

$P(X \leq 5) = 1 - e^{-5*0.5} = 0.9179$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9179 = 0.0821$

(b) lambda=0.9

$P(X \leq 5) = 1 - e^{-5*0.9} = 0.9889$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9889 = 0.0111$

(c) lambda=1.1

$P(X \leq 5) = 1 - e^{-5*1.1} = 0.9959$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9959 = 0.0041$

7 0

4 years ago

Round 1289.48 to the nearest dollar please

Ilya [14]

$1290 or you could use 1289.50

8 0

4 years ago

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