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BartSMP [9]
3 years ago
15

What is 15% of 76, rounded to two decimal places?

Mathematics
2 answers:
nlexa [21]3 years ago
8 0

Answer:

its 5.077

Step-by-step explanation:

you divide 75 by 15 which = to 5.066666667

then you round the first 6 to 7 and you get this

5.077 or 507.7 "don't mind me i ain't that good in math :("

galben [10]3 years ago
6 0

Answer: 11.4

Step-by-step explanation:

I did part / whole = % / 100

So x / 76 = 15 / 100

76 x 15 = 1140

1140 ÷ 100 = 11.4

You might be interested in
A basketball coach will select the members of a five-player team from among 9 players, including John and Peter. If the five pla
vivado [14]

Answer:

Step-by-step explanation:

Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.

Out of nine players five are chosen at random.

The team consists of John and Peter.

Hence we can sort 9 players as I group, John and Peter and II group 7 players.

Now the selection is 2 from I group and remaining 3 from II group.

Hence no of ways of selecting a team that includes both John and Peter=2C2*7C3=35

Total no of ways = 9C5=126

= \frac{2C2*7C3}{9C5}=\frac{35}{126} =\frac{5}{18}

6 0
3 years ago
What percent id 25 of 100?
Cloud [144]
25/100 is equal to 25%.

Percents are always out of 100.
So 25/100 is 25%.

Hope this helped☺☺
6 0
3 years ago
Lizzie rolls two dice. What is the probability that the sum of the dice is:
zhenek [66]

Answer:

A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A)  = \dfrac{12}{36} = \dfrac{1}{3}

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)}  Count 1

Possible cases for sum 3: {(1,2), (2,1)}  Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)}  Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)}  Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

P(B)  = \dfrac{15}{36} = \dfrac{5}{12}

C. Divisible by 3 and less than 7:

P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

P(A \cap B) = \dfrac{7}{\text{36}}

5 0
3 years ago
9.7q = 9.1q - 7.92<br> q =
AleksAgata [21]

Answer:

q = -13.2

Step-by-step explanation:

9.7q = 9.1q - 7.92

Subtract 9.1q from both sides.

0.6q = -7.92

Divide both sides by 0.6

q = -13.2

Double check your work.

9.7(-13.2) = 9.1(-13.2) - 7.92

-128.04 = -120.12 - 7.92

-128.04 = -128.04

5 0
3 years ago
Is 7 a soluion of 5x-3=12?
Ket [755]
Hi there,

No, it isn't

5x - 3 = 12
5x = 12 + 3
5x =15

Hence, X = 3

3 is the solution

Hope this helps :)
5 0
3 years ago
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