What is 540 into standard form

Mathematics

1 answer:

jok3333 [9.3K]2 years ago

6 0

Answer:

5.40 x $10^{2}$

Step-by-step explanation:

hoped that helped:P

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Suppose the selling price of homes is skewed right with a mean of 350,000 and a standard deviation of 160000 If we record the se

lys-0071 [83]

Answer:

The distribution will be approximately normal, with mean 350,000 and standard deviation 25,298.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

Suppose the selling price of homes is skewed right with a mean of 350,000 and a standard deviation of 160000

Sample of 40

Shape approximately normal

Mean 350000

Standard deviation $s = \frac{160000}{\sqrt{40}} = 25298$

The distribution will be approximately normal, with mean 350,000 and standard deviation 25,298.

5 0

3 years ago

Read 2 more answers

The price of admission to an amusement park is $35 for adults and $25 for children. a group of 14 people visit the park and pay

grandymaker [24]

X+y=14 (*25)
35x+25y=410
---------------------
35x+25y=410
25x+25y=350
---------------------
10x=60
x=6

6 0

3 years ago

There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro

elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that $\mu = 20.1, \sigma = 5.1$ .