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Stella [2.4K]
3 years ago
11

McKenzie runs 1.5 mi every 10 min.

Mathematics
1 answer:
mylen [45]3 years ago
8 0
If McKenzie runs 1.5 mp10m, multiply 1.5 by 6. McKenzie runs 9 miles per hour.
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An island has some portion submerged in water. Point A on the island is at negative 7 over 3 feet from the surface of the sea. P
sashaice [31]

Answer:

1/6feet

Step-by-step explanation:

Given

Point A on the island = -7/3 feet from the sea surface

Point B on the island = -5/2 from the sea surface

The distance between the two points will be Point A - Point B

Distance between the two points = -7/3 - (-5/2)

= -7/3+5/2

Find the LCM

= {2(-7)+3(5)}/6

= -14+15/6

= 1/6

Hence the distance of the two points from the surface of the sea is 1/6feet

3 0
3 years ago
Read 2 more answers
Select all that apply.
Viktor [21]
Answer:


0.5


Explaintion: because it is half of the 50%
8 0
3 years ago
The quotient of the difference of a number and 24 divided by 8 is the same as the number divided by 6. How do I turn that into a
artcher [175]
(24-x)/8=x/6
or 24-x=4x/3
24(3)-3x=4x
24(3)=7x
24(3)/7=x
7 0
3 years ago
Today, Sean left home at 8\text{ a.m.}8 a.m.8, start text, space, a, point, m, point, end text, drove to work, and worked from 9
EastWind [94]

Answer:

why yes

Step-by-step explanation:

8 0
3 years ago
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What are the period and phase shift for f(x) = −4 tan(x − π)?
nadya68 [22]
\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% function transformations for trigonometric functions
% templates
f(x)=Asin(Bx+C)+D
\\\\
f(x)=Acos(Bx+C)+D\\\\
f(x)=Atan(Bx+C)+D
\\\\
-------------------

\bf \bullet \textit{ stretches or shrinks}\\
~~~~~~\textit{horizontally by amplitude } A\cdot B\\\\
\bullet \textit{ flips it upside-down if }A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }B\textit{ is negative}

\bf ~~~~~~\textit{reflection over the y-axis}
\\\\
\bullet \textit{ horizontal shift by }\frac{C}{B}\\
~~~~~~if\ \frac{C}{B}\textit{ is negative, to the right}\\\\
~~~~~~if\ \frac{C}{B}\textit{ is positive, to the left}\\\\
\bullet \textit{vertical shift by }D\\
~~~~~~if\ D\textit{ is negative, downwards}\\\\
~~~~~~if\ D\textit{ is positive, upwards}

\bf \bullet \textit{function period or frequency}\\
~~~~~~\frac{2\pi }{B}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
~~~~~~\frac{\pi }{B}\ for\ tan(\theta),\ cot(\theta)

with that template in mind, let's see this one.

\bf f(x)=\stackrel{A}{-4}tan(\stackrel{B}{1}x\stackrel{C}{-\pi })+\stackrel{D}{0}
\\\\\\
\stackrel{period}{\cfrac{2\pi }{B}\implies \cfrac{2\pi }{1}\implies 2\pi }
\\\\\\
\stackrel{phase/horizontal~shift}{\cfrac{C}{B}\implies \cfrac{-\pi }{1}}\implies -\pi \qquad \textit{shifted to the right by }\pi \textit{ units}
3 0
3 years ago
Read 2 more answers
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