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GuDViN [60]
3 years ago
7

Only regular polygons with an even number of sides are symmetrical? True or false?

Mathematics
2 answers:
melamori03 [73]3 years ago
8 0
False i took the thing for apex 
USPshnik [31]3 years ago
7 0

Answer:

The given statement:

Only regular polygons with an even number of sides are symmetrical is a FALSE STATEMENT.

Step-by-step explanation:

A symmetrical figure or a polygon means that if it is into halves such that the halves looks similar or match exactly then the figure is said to be symmetrical.

We know that a regular polygon with 'n' number of sides has exactly n number of axis of symmetry.

Hence, no matter whether the regular polygon has even number of sides or odd number of sides it will be symmetrical.

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What is the height of the building?<br><br> 33.9 m<br> 37.1 m<br> 36.8 m<br> 34.5 m
madreJ [45]
37.1
Hope this helps a lot!!
5 0
3 years ago
Amy has 1/2 hour to do 3 chores. She plans to spend the same fraction of an hour on each chore. She wants to use the number line
Natali5045456 [20]
Point A would be zero; Point B, the end of the 1/2-hour time interval, would be 1/2 (representing 1/2 hour).  Then Amy needs to subdivide the interval A to B into three equal time intervals and to determine the length of each of these subintervals.

I would begin with 1/2 and divide that by 3:  

1
--
2
====
   3
   --
    1

Inverting the fraction in the denom. and multiplying, we get

1      1       1
-- * ---- = -----
2      3        6

So Amy will spend 1/6 th of an hour, or 10 minutes, on each chore.

Note that 3 times 1/6 comes out to 1/2 (hour), which is were we started.

5 0
3 years ago
Write out " Eleven Thousand Eleven Hundred Eleven" numerically.
lora16 [44]
The answer would be 11,111
7 0
4 years ago
What is the p-value? -- Researcher Jessie is studying how the fear of going to the dentist affects an adult's actual number of v
Vesnalui [34]

Answer:

Two, one for the 14 responses (number of visits) by the adults who fear going to the dentist and one for the 31 responses (number of visits) by the adults who do not fear going to the dentist.

Step-by-step explanation:

Hello!

1)

You want to test if the average visits to the dentist of people who fear to visit it are greater than the average visits of people that don't fear it.

In this case, the statistic to use is a pooled Student t-test. The reason I've to choose this test is that one of your sample sizes is small (n₁= 14) and the t-test is more accurate for small samples. Even if the second sample is greater than 30, if both variables are normally distributed, the pooled t-test is the one to use.

H₀: μ₁ = μ₂

H₁: μ₁ > μ₂

α: 0.10

t=<u> (X₁[bar]-X₂[bar]) - (μ₁ - μ₂)</u> ~ t_{n₁+n₂-2}

        Sₐ√(1/n₁+1/n₂)

Where

X₁[bar] and X₂[bar] are the sample means of both groups

Sₐ is the pooled standard deviation

This is a one-tailed test, you will reject the null hypothesis to big numbers of t. Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis), and in this case, is also one-tailed.

P(t_{n₁+n₂-2} ≥ t_{H0}) = 1 - P(t_{n₁+n₂-2} < t_{H0})

Where t_{H0} is the value of the calculated statistic.

Since you didn't copy the data of both samples, I cannot calculate it.

2)

Well there was one sample taken and separated in two following the criteria "fears the dentist" and "doesn't fear the dentist" making two different samples, so this is a test for two independent samples. To check if both variables are normally distributed you need to make two QQplots.

I hope it helps!

3 0
4 years ago
(x-2)+(y-16)=169 what's the circles radius
bija089 [108]
The anwser is x=187-y
4 0
3 years ago
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