Oliver uses the gcf and the distributive property to rewrite this summer 64+96

den301095 [7]

Answer:
15 feet

Explanation:
Triangle ABC is similar to triangle EDC, meaning they would’ve been congruent if it weren’t for their size.
This also means they don’t have the same side lengths but have the same proportions in comparison to each other.

The sides on the two triangles also correspond with each other. For example, line DC corresponds with line BC.
Knowing that, we can conclude that line ED also corresponds with line AB. Line ED is 12 ft and line AB is 4 ft. To get from 4 to 12, you multiply 3 (4*3=12).

Line EC also corresponds to line AC. So to calculate for line EC, we multiply the length of line AC by 3. 5*3=15, so therefore line EC is equal to 15.

5 0

4 years ago

¿Se pueden aplicar las razones trigonométricas de ángulos fijos para resolver cualquier tipo de triangulo?

DerKrebs [107]

Answer:

Solo se puede usarlas con triángulos rectángulos (right triangles en ingles).

5 0

4 years ago

What is the slope and the y-intercept of the line on the graph below? On a coordinate plane, a line goes through points (0, 1) a

DedPeter [7]

The slope is the change in Y over the change in x:

Slope = (0-1) / 4-0) = -1/4

Slope = -1/4

Y intercept is the Y value when x is equal to 0. In the point (0,1) x is 0 and y is 1, so the y-intercept is 1

3 0

3 years ago

Read 2 more answers

Two thirds of a number decreased by six is two. what is the number?

Kisachek [45]

Answer: The number is: " 12 ".

____________________________________
Let "x" represent "the unknown number" (for which we wish to solve.

The expression:

$\frac{2}{3}$ x − 6 = 2 ; Solve for "x" ;
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Method 1)

Add "6" to EACH SIDE of the equation;
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→ $\frac{2}{3}$ x − 6 + 6 = 2 + 6 ;

to get:

→ $\frac{2}{3}$ x = 8 ;
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Multiply each side of the equation by " $\frac{3}{2}$ " ; to isolate "x" on one side of the equation ; and to solve for "x" ;
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→ $\frac{3}{2}$ * $\frac{2}{3}$ x = 8 * $\frac{3}{2}$ ;

→ x = 8 * $\frac{3}{2}$ ;

= $\frac{8}{1}$ * $\frac{3}{2}$ ;

= $\frac{8*3}{1*2}$ ;

= $\frac{24}{2}$ ;

= 12 .
______________________________________________
x = 12 .
______________________________________________
Method 2)
______________________________________________
$\frac{2}{3}$ x − 6 = 2 ; Solve for "x" ;

Add "6" to EACH SIDE of the equation;
_______________________________________________
→ $\frac{2}{3}$ x − 6 + 6 = 2 + 6 ;

to get:
→ $\frac{2}{3}$ x = 8 ;
______________________________________________
Multiply each side of the equation by "3" ; to get rid of the "fraction" ;
 → 3 * $\frac{2}{3}$ x = 8 * 3 ;
→ $\frac{3}{1}$ * $\frac{2}{3}$ x = 8 * 3 ;
→ $\frac{3*2}{1*3}$ x = 8 * 3
→ $\frac{6}{3}$ x = 24 ;

→ 2x = 24 ;

→ Divide each side of the equation by "2" ; to isolate "x" on one side of the equation; & to solve for "x" :

2x / 2 = 24 / 2 ;

x = 12 .
__________________________________________________
Method 3).
__________________________________________________
$\frac{2}{3}$ x − 6 = 2 ; Solve for "x" ;
_______________________________________________
Add "6" to EACH SIDE of the equation;
_______________________________________________
→ $\frac{2}{3}$ x − 6 + 6 = 2 + 6 ;

to get:

→ $\frac{2}{3}$ x = 8 ;
______________________________________________
Now, divide each side of the equation by " $\frac{2}{3}$ " ;
to isolate "x" on one side of the equation; & to solve for "x" ;
___________________________________________________
{ $\frac{2}{3}$ x } / { $\frac{2}{3}$ } = 8 / { $\frac{2}{3}$ } ;

to get: x = 8 / { $\frac{2}{3}$ } ;

= 8 * ( $\frac{3}{2}$ ;

= $\frac{8}{1}$ * $\frac{3}{2}$ ;

= $\frac{8*3}{1*2}$ ;

= $\frac{24}{2}$ ;

= 12 ;
___________________________________________
x = 12 .
___________________________________________
NOTE: Variant: (in "Methods 2 & 3") :
___________________________________________
At the point where:
___________________________________________
= 8 * ( $\frac{3}{2}$ ) ;

= $\frac{8}{1}$ * $\frac{3}{2}$ ;
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We can cancel out the "2" to a "1" ; and we can cancel out the "8" to a "4" ;
__________________________________________
{since: "8÷2 = 4" ; and since: "2÷2 =1" } ;
__________________________________________
and we can rewrite the expression:
__________________________________________
$\frac{8}{1}$ * $\frac{3}{2}$ ;
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as: $\frac{4}{1}$ * $\frac{3}{1}$ ;
__________________________________________
which equals:
__________________________________________
→ $\frac{4*3}{1*1}$ ;

= $\frac{12}{1}$ ;

= 12 .
__________________________________________
x = 12 .
__________________________________________
Answer: The number is: " 12 ".
__________________________________________

8 0

4 years ago

[39 POINTS] If <img src="https://tex.z-dn.net/?f=%20x%5E5k%3Da%5C%5C%20x%5E2k%5E2%3Db%20" id="TexFormula1" title=" x^5k=a\\

rjkz [21]

Given

x^5*k=a .................(1)

x^2*k=b .................(2)

We need to find x^3.

Solution:

On inspection, we note that (1)/(2) gives x^3 on the left hand side, but the division is valid on conditions that x ≠ 0 and k ≠ 0.

So we conclude:

(1) / (2)