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Dominik [7]
3 years ago
9

Oliver uses the gcf and the distributive property to rewrite this summer 64+96

Mathematics
1 answer:
Rashid [163]3 years ago
6 0
<span>64+96 = 32 (2 + 3)

............................................</span>
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B is the midpoint of AC. AB= 3(3x-1) and AC=5(2x+2) find X, AB, BC, and AC
VMariaS [17]

Answer:

x = 2

Step-by-step explanation:

AB is given as 3(3x-1) multiply inside the parenthesis with 3

AB = 9x - 3

AC is given as 5(2x+2) multiply inside the parenthesis with 5

AC = 10x + 10

if B is midpoint of AC then AB = BC and AC = AB + BC if we write this equation using the given values

9x - 3 + 9x - 3 = 10x + 10 add like terms

18x - 6 = 10x + 10 transfer like terms to the same side of the equation

18x - 10x = 10 + 6

8x = 16 divide both sides by 8

x = 2 replace x with 2 in given expressions to find the value of each component

4 0
2 years ago
Read 2 more answers
What is the range of the function?<br>(1,2) (2,4) (3,9) (4,16)<br>​
Brut [27]

Answer:

{ 2 , 4 , 9 , 16 }

Step-by-step explanation:

7 0
4 years ago
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3 Z The quadratic equation whose roots twice the roots of :2X2-8X+5=0​
lubasha [3.4K]
Ok done. Thank to me:>
5 0
3 years ago
What is the slope of this line​
Rashid [163]

Answer:

Slope = 2/3

Step-by-step explanation:

Slope = Change over y (rise) over change over x (run)

Pick two dot points on the line

Count how many units over they are until you get to the next dot, then count how many units up until you reach the next dot

Remember: Y runs vertically, X runs horizontally

Put the unit number that ran vertically on the top, then put the unit number that runs horizontally on the bottom

If needed simplify

The slope is 2/3

5 0
4 years ago
(X^3+1)dividend (x-1)
bazaltina [42]

x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

(x^3+1)-(x^3-x^2)=x^2+1

x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

(x^2+1)-(x^2-x)=x+1

x=x\cdot1 and 1(x-1)=x-1. Subtracting this from the previous remainder gives a new one of

(x+1)-(x-1)=2

and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

4 0
3 years ago
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