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ArbitrLikvidat [17]
3 years ago
11

A man measured his height and found 5.7 feet. However, after he carefully measured his height a second time, he found his real h

eight to be 5 feet.What is the percent error the man made the first time he measured his height?
Mathematics
2 answers:
Lina20 [59]3 years ago
5 0

Answer:

percentage error = 12.28%

Step-by-step explanation:

5 x 0.14 = 0.7

5 x 1.14 = 5.7

as increase is not the same as error decrease.

We use the same numbers 12.28% = 0.1228.

5.7 x 0.1228 = 0.69996  = 12.28%

5.7 - 0.69996 = 5.00004 foot.  As decrease.

And find it is correct.

His error therefore was 12.28% out.

As we work the first numbers 5.7 and can only x by a number to see 5ft

We take 5.7 x 0.1228 and find 0.69996 when taken from 5.7 ft. is unmistakably 5 foot.  (5.00004) ft.

butalik [34]3 years ago
5 0

Answer:

14%

Step-by-step explanation:

percent error = (experimental measure - real measure)/(real measure) * 100%

percent error = (5.7 ft - 5 ft)/(5 ft) * 100%

percent error = (0.7 ft)/(5 ft) * 100%

percent error = 0.14 * 100%

percent error = 14%

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