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AlladinOne [14]
3 years ago
10

A meteorologist used the expression below to describe how the temperature changed. –5 + (–4) Which statement could describe how

the temperature changed? The temperature was –5 degrees, then it increased 4 degrees. The temperature was –5 degrees, then it decreased 4 degrees. The temperature was 5 degrees, then it increased 4 degrees. The temperature was 5 degrees, then it decreased 4 degrees.
Mathematics
2 answers:
saw5 [17]3 years ago
6 0
The answer is
The temperature was -5°, then it decreased 4°
Mkey [24]3 years ago
4 0

Answer:

The temperature was –5 degrees, then it decreased 4 degrees.

Step-by-step explanation:

Expression : -5+(-4)

A meteorologist used this expression to describe how the temperature changed.

Since temperature was -5.

Now,temperature is :

-5+(-4)

-9

So, initially temperature was - 5 and now the temperature is -9 .

So,it decreased 4 degrees.

Thus we can conclude that The temperature was –5 degrees, then it decreased 4 degrees.

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-17x + 2 +3x^2 + 2x^3 divided by x-2
Stells [14]

Answer:

2x^2+7x-3

remainder is -4

Step-by-step explanation:

Check the image

6 0
3 years ago
If z^2+1/z^2=11 , find the value of z^3-1/z^3,using only the positive value of z-1/z
vredina [299]
Hello,

Let's assume

t=z- \dfrac{1}{z} \\\\

t^2=z^2-2+ \dfrac{1}{z^2}= 11-2=9==\ \textgreater \ t=3\\\\

t^3=z^3-3z^2* \dfrac{1}{z} +3z* \dfrac{1}{z^2} - \dfrac{1}{z^3} \\\\
=z^3 - \dfrac{1}{z^3} -3(z-\dfrac{1}{z})\\\\
z^3 - \dfrac{1}{z^3}=t^3+3t=3^3+9=27+9=36



7 0
3 years ago
The perimeter of a playing field for a certain sport is 214 ft. The field is a rectangle, and the length is 41 ft longer than th
malfutka [58]

Step-by-step explanation:

Perimeter of a rectangle = 2(L+W)

L is the length of the rectangle:

W is the width of the rectangle.

Given

Perimeter = 214feet

If the length is 41 ft longer than the width, then L = 41+W

Substitute L = 41+W into the formula:

P = 2(L+W)

214 = 2(41+W+W)

214 = 2(41+2W)

214 = 82+4W

4W = 214-82

4W = 132

W = 132/4

W = 33 feet

Since L = 41+W

L = 41+33

L = 74 feet

Hence the dimension of the field is 74ft by 33ft

<em>The width of the playing field is 33feet</em>

8 0
3 years ago
Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?
Tema [17]

Answer:

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Step-by-step explanation:

We are given that

f(x)=tan(x)-\frac{2}{x}

g(x)=x^2+8

We have to find f(x)\times g(y)

To find the value of f(x)\times g(y) we will multiply f(x) by g(y)

g(y)=y^2+8

Now,

f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)

f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Hence,

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

5 0
3 years ago
if alpha and beta are the zeros of the quadratic polynomial FX = x square - 5 x + 4 find the value of one by alpha + 1 by beta-2
Kryger [21]

Answer:

suggestions use math scanner or mathaway or algebra calculator they will provide the steps and answer

5 0
3 years ago
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