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AlladinOne [14]
4 years ago
10

A meteorologist used the expression below to describe how the temperature changed. –5 + (–4) Which statement could describe how

the temperature changed? The temperature was –5 degrees, then it increased 4 degrees. The temperature was –5 degrees, then it decreased 4 degrees. The temperature was 5 degrees, then it increased 4 degrees. The temperature was 5 degrees, then it decreased 4 degrees.
Mathematics
2 answers:
saw5 [17]4 years ago
6 0
The answer is
The temperature was -5°, then it decreased 4°
Mkey [24]4 years ago
4 0

Answer:

The temperature was –5 degrees, then it decreased 4 degrees.

Step-by-step explanation:

Expression : -5+(-4)

A meteorologist used this expression to describe how the temperature changed.

Since temperature was -5.

Now,temperature is :

-5+(-4)

-9

So, initially temperature was - 5 and now the temperature is -9 .

So,it decreased 4 degrees.

Thus we can conclude that The temperature was –5 degrees, then it decreased 4 degrees.

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Cos (0) = square root 2/2 and 3pi/2<0<2 pi , evaluate sin(0) and tan (0)
katovenus [111]

Answer:

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Step-by-step explanation:

Given : \cos\theta=\frac{\sqrt2}{2} and \frac{3\pi}{2}

To find : Evaluate \sin\theta and \tan\theta ?

Solution :

As \frac{3\pi}{2} means \theta belong to the third or fourth quadrant .

So,   \sin\theta is negative and \tan\theta is positive in third and negative in fourth.

Using the formula of trigonometric,

\sin^2\theta+\cos^2\theta=1

\sin\theta=\sqrt{1-\cos^2\theta}

Substitute  \cos\theta=\frac{\sqrt2}{2} ,

\sin\theta=\pm\sqrt{1-(\frac{\sqrt2}{2})^2}

\sin\theta=\pm\sqrt{1-\frac{2}{4}}

\sin\theta=\pm\sqrt{1-\frac{1}{2}}

\sin\theta=\pm\sqrt{\frac{1}{2}}

\sin\theta=-\frac{\sqrt2}{2}}

Now using another formula,

\tan\theta=\frac{\sin\theta}{\cos\theta}

\tan\theta=\frac{-\frac{\sqrt2}{2}}{\frac{\sqrt2}{2}}

\tan\theta=-1

Therefore, \sin\theta=-\frac{\sqrt2}{2}} and \tan\theta=-1.

7 0
3 years ago
26=8+v I dont know how to do this and I need help
Goshia [24]
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First, 
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Second, simplify 26 - 8 to get 18. Your problem should look like 18 = v.
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3 years ago
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seropon [69]

Answer:

The scale factor is 1.5! I hope this helps!

8 0
3 years ago
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The slope of a line is 5 /7. What is the slope of any line that is perpendicular to that line?
Lady bird [3.3K]

Answer:

-7/5

Step-by-step explanation:

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4 0
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