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Fynjy0 [20]
3 years ago
7

The perimeter of a playing field for a certain sport is 214 ft. The field is a rectangle, and the length is 41 ft longer than th

e width. Find the dimensions
The width of the playing field is

(Type an integer or a decimal)
Mathematics
1 answer:
malfutka [58]3 years ago
8 0

Step-by-step explanation:

Perimeter of a rectangle = 2(L+W)

L is the length of the rectangle:

W is the width of the rectangle.

Given

Perimeter = 214feet

If the length is 41 ft longer than the width, then L = 41+W

Substitute L = 41+W into the formula:

P = 2(L+W)

214 = 2(41+W+W)

214 = 2(41+2W)

214 = 82+4W

4W = 214-82

4W = 132

W = 132/4

W = 33 feet

Since L = 41+W

L = 41+33

L = 74 feet

Hence the dimension of the field is 74ft by 33ft

<em>The width of the playing field is 33feet</em>

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Find the volume in cm^3 of a right circular cylinder with a radius of 10 cm and height of 14 cm
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