The perimeter of a playing field for a certain sport is 214 ft. The field is a rectangle, and the length is 41 ft longer than th
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Answer:
Slope of required line if both lines are parallel: y=4x-20
Slope of required line if both lines are perpendicular: y=-1/4x+14
Step-by-step explanation:
We need to find equation of line while we are given another line having equation y=4x-6 and passes through point (8,12)
<u><em>Note: Since it is not given if the required line is parallel or perpendicular to the given line. I will solve for both cases.</em></u>
If Both lines are parallel the equation of new line will be:
We need to find slope and y-intercept to write equation of new line.
When lines are parallel there slopes are same
So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)
Slope of new line is: m=4
Now finding y-intercept
Using slope m=4 and point (8,12) we can find y-intercept
y-intercept of new line is: b=-20
Equation of required line having slope m=4 and y-intercept b=-20 is
If Both lines are perpendicular the equation of new line will be:
We need to find slope and y-intercept to write equation of new line.
When lines are perpendicular there slopes are opposite of each other
So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)
Slope of new line is: m=-1/4
Now finding y-intercept
Using slope m=-1/4 and point (8,12) we can find y-intercept
y-intercept of new line is: b=14
Equation of required line having slope m=-1/4 and y-intercept b=14 is
Answer:
No, we can't reject the dealer's claim with a significance level of 0.05.
Step-by-step explanation:
We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.
You take a random sample of 600 cars in San Francisco and find that 141 are blue.
<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>
SO, Null Hypothesis, : p = 25% {means that 25% of all cars in San Francisco are blue}
Alternate Hypothesis, : p
25% {means that % of all cars in San Francisco who are blue is different from 25%}
The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;
T.S. = ~ N(0,1)
where, = sample proportion of 600 cars in San Francisco who are blue =
= 0.235
n = sample of cars = 600
So, <u><em>test statistics</em></u> =
= -0.866
<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>
Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.