Do you mean as a decimal? 11.8
Answer:
Step-by-step explanation:
Given
Required
Eliminate a
Multiply the first equation by -4
Add to the second equation
Solve brackets
Open bracket
At this point, a has been eliminated;
From the list of given options, the option that answers the question is
Answer:
D
Step-by-step explanation:
For simplify the work we can start to factorise all the possibles expressions:
2x + 8.
8 is multiple of 2, so it can became
2(x+4)
x^2 - 16 this is a difference of two squares, so it can be rewritten as:
(x+4)(x-4)
x^2 + 8x + 16
we have to find two numbers whose sum is 8 and whose product is 16
the two number are 4 and 4
it becames:
(x+4)(x+4)
x+ 4 can‘t be simplified
if we look at the expression, we can find that x-4 appears at the numerator so
x^2 - 16 must be at numerator
but the second factor (x+4) doesn’t appear, so has been simplified. This situation can be possible only in the D option
in fact
(x+4)(x-4)/2(x+4) * (x+4)/(x+4)(x+4)
it became
(x+4)(x-4)/2 * 1/(x+4)(x+4)
(x-4)/2(x+4)
SRT = 20 => STR = 20.
Since STR and STU are supplementary angles, STU = 180 - STR = 180 - 20 = 160, means x = 40.
4x^6 / (2x - 6)
4x^6 / 2(x - 3)
2x^6 / (x - 3)
