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Nadya [2.5K]
4 years ago
8

Respuesta de 17 entre 264. 31

Mathematics
1 answer:
Alexxandr [17]4 years ago
4 0
<span>0.0643184139836

creo que a eso te refieres!!!

hay una paguina de brainly en espanol ahi tambien te pueden ayudar

es:brainly.lat


</span>
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6 3/4 + 3 1/8 please whats the answer
Natalka [10]

Answer:

9 7/8 is the answer, hope this helps!

Step-by-step explanation:

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3 years ago
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Solve for an angle in right triangles
Aneli [31]

Answer:

90

Step-by-step explanation:

if all the interior angle in triangle sums up it will be 180

so 180 divide by by 3(because its a triangle) is 90

hope this helps

have a nice day <3

8 0
2 years ago
Sal and Jen went to the store together, and each bought the same car stereo.
scZoUnD [109]

Answer: Sal used a debit card and paid a total of $324.80 for the stereo. (I took the test too)

Step-by-step explanation: Multiply $21.30 by 18 months. Then subtract the interest, $58.60, from the product because Sal paid immediately with a card which implies using a debit card. You get $324.80.

8 0
3 years ago
I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
3 years ago
Find the selling price for the item flash drive: $12 markup:35%​
vesna_86 [32]

Answer:

16.2

Step-by-step explanation:

12*1.35=16.2

(can I get brainliest pls)

4 0
3 years ago
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