For the first 6 trips she walked 3.2 kilometers and for the next 6 she made another 3.2 which would be 6.4 kilometers for 12 trips now she made 3 more trips which is half of the amount she originally did so it would be half of the distance also so 3.2 divided by 2 is 1.6 kilometers so for the last 3 trips she walked 1.6 kilometers. now add up all the distance she walked so 6.4 kilometers for the 12 trips plus the 1.6 for the other 3 trips is 8 kilometers in total. she walked 8 kilometers after 15 trips.
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Given triangle ABC with altitude segment BD labeled x. Angles ADB and CDB are right angles by _____1._____, making triangle ABD and triangle BCD right triangles. Using the trigonometric ratios sine of A equals x over c and sine of C equals x over a. Multiplying to isolate x in both equations gives x = _____2._____ and x = a ⋅ sinC. We also know that x = x by the reflexive property. By the substitution property, _____3._____. Dividing each side of the equation by ac gives: sine of A over a equals sine of C over c.
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1 is the constant
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I think it is b
I hope it is right and have a lovely day
