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xxTIMURxx [149]
4 years ago
12

If angle ZYX measures 23 degrees, then arc XY measures 45 degrees. True or False?

Mathematics
1 answer:
Over [174]4 years ago
8 0
The statement "If angle ZYX measures 23 degrees, then arc XY measures 45 degrees." is considered as True. It can be computed using the major and minor arcs of a circle. I hope my answer has come to your help. God bless and have a nice day ahead!
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What is opposite negative 7 5 over 12
coldgirl [10]
The opposite of negative 75 over 12? The answer would be negative 16
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7 0
4 years ago
Which equation gives the length of the altitude of ABC?
Alborosie

Answer:

B. AD = sqrt(CD * BD)

Step-by-step explanation:

By the right triangle altitude theorem,

CD/AD = AD/BD

AD^2 = CD * BD

AD = sqrt(CD * BD)

Answer: B. AD = sqrt(CD * BD)

5 0
3 years ago
Read 2 more answers
A group of friends in Chicago watched a televised bullfight. They ordered 3 pizzas ($15 each), 15 drinks ($1.50 each), and 6 lar
lara31 [8.8K]

Answer:

$127.875

Step-by-step explanation:

cost of 3 pizzas= $15*3

cost of 3 pizzas=$45

cost of 15 drinks=$1.50*15

cost of 15 drinks=$22.5

cost of 6 nachos=$5.80*6

cost of 6 nachos=$34.8

Total cost = pizza cost+ drinks+nachos

total cost=$45+$22.5+$34.8

total cost=$102.3

Now ,

Tip cost=$102.3*20%

=$20.46

tex cost=$102.3*5%

=$5.115

Bill which all friends pay=total cost+ tip cost+tex cost

= $102.3+$20.46+$5.115

=$127.875

3 0
3 years ago
Divide 9x ^ 3 + 18x ^ 2 - 13x + 5 by 3x - 1 using division and write the division in the form P = DQ + R
lana66690 [7]

Answer:

\frac{9x^3\:+\:18x\:^2\:-\:13x\:+\:5}{3x-1}=9x^3+18x^2-13x+5

Step-by-step explanation:

DIVISION ALGORITHM: If p(x) and d(x)\neq 0  are polynomials, and the degree of d(x) is less than or equal to the degree of f(x),  then there exist unique polynomials q(x) and r(x), so that

                                               \frac{p(x)}{d(x)} =q(x)+\frac{r(x)}{d(x)}

and so that the degree of r(x)  is less than the degree of d(x).

To find \frac{9 x^{3} + 18 x^{2} - 13 x + 5}{3 x - 1} you must:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}9x^3+18x^2-13x+5\\\mathrm{and\:the\:divisor\:}3x-1\mathrm{\::\:}\frac{9x^3}{3x}=3x^2

\mathrm{Quotient}=3x^2

\mathrm{Multiply\:}3x-1\mathrm{\:by\:}3x^2:\:9x^3-3x^2\\\mathrm{Subtract\:}9x^3-3x^2\mathrm{\:from\:}9x^3+18x^2-13x+5\mathrm{\:to\:get\:new\:remainder}\\

\mathrm{Remainder}=21x^2-13x+5

Therefore,

\frac{9x^3+18x^2-13x+5}{3x-1}=3x^2+\frac{21x^2-13x+5}{3x-1}

\mathrm{Divide}\:\frac{21x^2-13x+5}{3x-1}

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}21x^2-13x+54\\\mathrm{and\:the\:divisor\:}3x-1\mathrm{\::\:}\frac{21x^2}{3x}=7x\\\\\mathrm{Quotient}=7x

\mathrm{Multiply\:}3x-1\mathrm{\:by\:}7x:\:21x^2-7x\\\mathrm{Subtract\:}21x^2-7x\mathrm{\:from\:}21x^2-13x+5\mathrm{\:to\:get\:new\:remainder}\\\\\mathrm{Remainder}=-6x+5

Therefore,

\frac{21x^2-13x+5}{3x-1}=7x+\frac{-6x+5}{3x-1}\\\\\frac{9x^3+18x^2-13x+5}{3x-1}=3x^2+7x+\frac{-6x+5}{3x-1}

\mathrm{Divide}\:\frac{-6x+5}{3x-1}

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-6x+5\\\mathrm{and\:the\:divisor\:}3x-1\mathrm{\::\:}\frac{-6x}{3x}=-2\\\\\mathrm{Quotient}=-2

\mathrm{Multiply\:}3x-1\mathrm{\:by\:}-2:\:-6x+2\\\mathrm{Subtract\:}-6x+2\mathrm{\:from\:}-6x+5\mathrm{\:to\:get\:new\:remainder}\\\\\mathrm{Remainder}=3

Therefore,

\frac{-6x+5}{3x-1}=-2+\frac{3}{3x-1}\\\\\frac{9x^3+18x^2-13x+5}{3x-1}=3x^2+7x-2+\frac{3}{3x-1}

6 0
4 years ago
An interior designer wants to decorate a newly constructed house. The function f(x) = 36×2 – 150 represents the amount of money
goldenfox [79]

We want to use the given functions to create another function that models the revenue of the worker as a function of the time he works.

The solutions are:

A) r(x) = x^2 - 150

B) $1,850

C) The difference quotient is equal to 2*x.

We have two functions:

f(x) = 36*x^2 - 150

f(x) is the amount of money that he wins for decorating x rooms.

g(x) = (1/6)*x

g(x) is the number of rooms that he decorates in x hours.

So the revenue as a function of time can be given by evaluating f(x) in g(x).

A) we get:

r(x)  f( g(x)) = 36*[(1/6)*x]^2 - 150 = x^2 - 150

r(x) = x^2 - 150

B) If he works for 45 hours, we just need to replace x by 45 in the revenue equation:

r(45) = 45^2 - 150 = 1,875

Meaning that he would win $1,875 for 45 hours of work.

C) the difference quotient for a function f(x) is given by:

\lim_{h \to 0}  \frac{f(x + h) - f(x)}{h}

For the case of r(x) we have:

\lim_{h \to 0}  \frac{r(x + h) - r(x)}{h} = \lim_{h \to 0}  \frac{(x + h)^2 - 150 - x^2 + 150}{h} = \lim_{h \to 0}   \frac{x^2 + 2xh + h^2 - x^2}{h} = 2x

If you want to learn more, you can read:

brainly.com/question/2581441

3 0
3 years ago
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