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aleksandrvk [35]
2 years ago
12

Chromium-51 has a half-life of 28 days. If Georgia leaves a bottle of 10,000-milligram capsules in her medicine cabinet for a ye

ar, what will be the strength in milligrams of each capsule? Round to the nearest milligram
Mathematics
1 answer:
QveST [7]2 years ago
8 0

For finding the strength of the capsules after one year, we will use half-life formula. The formula is:

A = A₀ (\frac{1}{2})^\frac{t}{h}

where, A= Final amount

A₀ = Initial amount

t= time elapsed

h= half-life

Here, in this problem A₀ = 10000 milligram, t= 1 year or 365 days

and h= 28 days

So, A = 10000 (\frac{1}{2} )^\frac{365}{28}

⇒ A = 10000 (\frac{1}{2})^1^3^.^0^4

⇒ A = 1.187

So, the strength of the capsules after one year will be 1.187 milligrams.

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What is the slope of a line that is perpendicular to the line y= 1/3 x - 2
drek231 [11]

Answer:

slope = - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{1}{3} x - 2 ← is in slope- intercept form

with slope m = \frac{1}{3}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{1}{3} } = - 3

4 0
3 years ago
A delivery truck drives three routes in one day. The first route is 1223 miles long, the second route is 1034 miles long, and th
avanturin [10]

Answer:

Total = 38\frac{11}{12}\ miles

Step-by-step explanation:

Given

First\ Route = 12\frac{2}{3}\ miles

Second\ Route = 10\frac{3}{4}\ miles

Third\ Route = 15\frac{1}{2}\ miles

Required

Determine the total miles

Total = First\ Route + Second\ Route + Third\ Route

Total = 12\frac{2}{3} + 10\frac{3}{4} + 15\frac{1}{2}

Convert to improper fractions

Total = \frac{38}{3} + \frac{43}{4} + \frac{31}{2}

Take LCM

Total = \frac{152 + 129 + 186}{12}

Total = \frac{467}{12}

Total = 38\frac{11}{12}\ miles

5 0
3 years ago
17.The diameter of a circle has endpoints P(–7, –10) and Q(3, 2).
ser-zykov [4K]
A.) (-2,-4)
(7+3)/2=5, (10+2)/2=6
(-7+5,-10+6)
(-2,-4)
b.)r^2=244
10^2+12^2=244
r=2(61)^(1/2)
c.)(x+2)^2+(y+4)^2=244
7 0
3 years ago
Please Help me with this question​
nevsk [136]

Answer:

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3 0
2 years ago
A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess
statuscvo [17]
Let's start by visualising this concept.

Number of grains on square:
1   2   4   8   16 ...

We can see that it starts to form a geometric sequence, with the common ratio being 2.

For the first question, we simply want the fifteenth term, so we just use the nth term geometric form:
T_n = ar^{n - 1}
T_{15} = 2^{14} = 16384

Thus, there are 16, 384 grains on the fifteenth square.

The second question begs the same process, only this time, it's a summation. Using our sum to n terms of geometric sequence, we get:
S_n = \frac{a(r^{n} - 1)}{r - 1}
S_{15} = \frac{2^{15} - 1}{2 - 1}
S_{15} = 2^{15} - 1 = 32767

Thus, there are 32, 767 total grains on the first 15 squares, and you should be able to work the rest from here.
6 0
2 years ago
Read 2 more answers
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