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AleksAgata [21]
3 years ago
8

What us 708,569 rounded to the ten thousands

Mathematics
1 answer:
leonid [27]3 years ago
3 0
Hey! The Answer Is 08000. Hoped i Helped!Please Put Brianlest answerPlzzzzzzzz
You might be interested in
Help needed asap.
aniked [119]
Answer: Choice C
The pink equation is y = 2x-3
The yellow equation is y = -2x+1

Notice how the pink equation crosses the y axis at (0,-3) or at -3 on the y number line. This tells us that the pink equation has a y intercept of -3. So b = -3
This only happens with the equation y = 2x-3. The other equations do not have a y intercept of -3. So this quickly rules out the other choices leaving C as the only answer.

An alternative is to find two points on the pink line, such as (0,-3) and (1,-1). Then find the slope of the line through those points. You should find the slope to be m = 2. So m = 2 and b = -3 leads to y = 2x-3. Follow similar steps for the yellow line as well.
6 0
4 years ago
Find the slope of the line through each pair of points.
Natali [406]

Answer:

1. 0, 2. -1/2, 3.undefined, 4. -5/3, 5. 6, 6. -2, 7. 23/17

Step-by-step explanation:

y2 - y1 / x2 - x1

1. -18 - -18 / 15 - 6 = 0

2. 16 - 12 / 0 - 8 = -4/8 = -1/2

3. 37 - 2 / -15 - -15 is undefined (can't have 0 as denominator)

4. 30 - 20 / -5 - 1 = 10 / -6 = -5/3

5. -36 - -12 / 4 - 8 = -24 / -4 = 6

6. - 23 - -15 / 11 - 7 = -8 / 4 = -2

7. 100 - 54 / -38 - -72 = 46 / 34 = 23/17

3 0
2 years ago
Read 2 more answers
the width of a rectangle is 8cm less then its length the perimeter of the rectangle is 52 cm. what is the width of the rectangle
BartSMP [9]
P=2L+2a
w=L-8, P=52
52=2L +2(L-8)
52=4L-16
68=4L
L=17, w=9
4 0
3 years ago
I need help with this problem from the calculus portion on my ACT prep guide
LenaWriter [7]

Given a series, the ratio test implies finding the following limit:

\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=r

If r<1 then the series converges, if r>1 the series diverges and if r=1 the test is inconclusive and we can't assure if the series converges or diverges. So let's see the terms in this limit:

\begin{gathered} a_n=\frac{2^n}{n5^{n+1}} \\ a_{n+1}=\frac{2^{n+1}}{(n+1)5^{n+2}} \end{gathered}

Then the limit is:

\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=\lim _{n\to\infty}\lvert\frac{n5^{n+1}}{2^n}\cdot\frac{2^{n+1}}{\mleft(n+1\mright)5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert

We can simplify the expressions inside the absolute value:

\begin{gathered} \lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert \\ \lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert=\lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert \\ \lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert=\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert \end{gathered}

Since none of the terms inside the absolute value can be negative we can write this with out it:

\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}

Now let's re-writte n/(n+1):

\frac{n}{n+1}=\frac{n}{n\cdot(1+\frac{1}{n})}=\frac{1}{1+\frac{1}{n}}

Then the limit we have to find is:

\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}

Note that the limit of 1/n when n tends to infinite is 0 so we get:

\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}=\frac{2}{5}\cdot\frac{1}{1+0}=\frac{2}{5}=0.4

So from the test ratio r=0.4 and the series converges. Then the answer is the second option.

8 0
1 year ago
BRAINLIESTT ASAP! PLEASE HELP ME :)
Yuliya22 [10]

Answer:

the building strong enough to withstand the denali quake

Step-by-step explanation:

the building strong enough to withstand the denali quake

Step-by-step explanation:

denali quake 6.7  x 70 = 469

the building in denali should be strong enough to withstand an earthquake of that magnitude  

rat island quake 7.8 x 30 = 234

the building in the rat islands should be strong enough to withstand an earthquake of that magnitude :)

8 0
3 years ago
Read 2 more answers
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