Solution:
<u>Note that:</u>
- 3x + 50 = 6x - 10 (Vertically opposite angles)
Simplify the equation to find x.
<u>Add 10 both sides.</u>
- 3x + 50 = 6x - 10
- => 3x + 50 + 10 = 6x - 10 + 10
- => 3x + 60 = 6x
<u>Subtract 3x both sides.</u>
- 3x + 60 = 6x
- => 3x - 3x + 60 = 6x - 3x
- => 60 = 3x
<u>Divide 3 both sides.</u>
- 60 = 3x
- => 60/3 = 3x/3
- => x = 20
17. 2/3
18. 1 1/9
20.9 1/11
21. 2 909/100 (closest i could get)
Hope I helped and hope you had a good day!
Answer:$31.05
Step-by-step explanation:
I added the hours then multiply by $3.45
The normal vectors to the two planes are (3, 3, 2) and (2, -3, 2). The cross product of these will be the direction vector of the line of intersection, (12, -2, -15).
Using x=0, we can find a point on this line by solving the simultaneous equations that remain:
... 3y +2z = -2
... -3y +2z = 2
Adding these, we get
... 4z = 0
... z = 0
so the point we're looking for is (x, y, z) = (0, -2/3, 0). This gives rise to the parametric equations ...
- x = 12t
- y = -2/3 -2t
- z = -15t
By letting t=2/3, we can find a point on the line that has integer coefficients. That will be (x, y, z) = (8, -2, -10).
Then our parametric equations can be written as
- x = 8 +12t
- y = -2 -2t
- z = -10 -15t
Answer:
14.86
Step-by-step explanation:
4.5+ 3.8+ 3.2 +2.3=16.7 divided by 5 which I got from how many numbers I added =14.86
