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Andrej [43]
4 years ago
5

What is the inverse of the function f(x) = 2x – 10?

Mathematics
1 answer:
VMariaS [17]4 years ago
4 0
The fourth option is correct. 1. Switch f(x) for y    2. Transfer -10 as a +10 to the left side of the equation. y + 10 = 2x.  3. Then last, divide both sides by 2 to leave the x alone of the right. Now you have x = 1/2y + 5. Now switch back the y and x so it becomes y = 1/2x + 5. Also, make the y an h(x) to finish up.
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State how many significant figures 0.03810 has?
guapka [62]

Answer:

4

Step-by-step explanation:

the figures are

0,0,3,8,1,0

we repeat 0

so we have 4 figures,

0,3,8,1

8 0
3 years ago
MARKING BRAINLIEST <br><br> PLS HELP
ch4aika [34]

Answer:

-7

Step-by-step explanation:

Domain is simply another way of saying input values. Input values are literally just x values (Any place on the x bar. Range is the same but instead of x values it is for y values.

5 0
3 years ago
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Analyze the diagram below and complete the instructions that follow.<br> Find the value of x.
liubo4ka [24]

Answer:

x=30

Step-by-step explanation:

2x=y-x

3x=y

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x=30.

7 0
3 years ago
The pattern of the scarf is 28 in and 15 in what is the area of the scarf
Soloha48 [4]
The area is 270 inches, because you would do length times width, which in this situation is 28 and 15. You multiply them, and you get 270.
6 0
3 years ago
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The number of violent crimes committed in a day possesses a distribution with a mean of 2.2 crimes per day and a standard deviat
VARVARA [1.3K]

Answer:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

Step-by-step explanation:

For this case we have the following info given:

\mu = 2.2 represent the mean

\sigma = 6 represent the deviation

We select a sample size of n=100. This sample is >30 so then we can use the central limit theorem. And we want to find the distribution for the sample mean and we know that the distribution is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

6 0
4 years ago
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