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3 years ago

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The coordinates of the vertices of a triangle are A(3, 3), B(6, 3), and C(6, 6). The coordinates of the vertices of its image ar

e A'(-3, -3), B'(-6, -3), and C'(-6, -6). Using complete sentences, describe what transformations would result in this image?

1 answer:

MariettaO [177]3 years ago

6 0

It would reflect over the x-axis and then reflect over the y-axis

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In the figure, ∠6 and ∠3 are ...

konstantin123 [22]

Answer:

They're supplementary angles AND same-side interior angles.

7 0

3 years ago

Find the co-ordinates of the point of trisection of the line joining the points A(1,8) and B(4,2).

Licemer1 [7]

<u>coordinates of the point are (2,6) and (3,4)</u>

Answer:

Solution given:

let the given point be A(1,8) and B(4,2).

P and Q are the two points on AB such that

AP=PQ=QB=k

now

comparing AP and PB

AP=k

PB=2k

ratio of AP and PB = $\frac{1k}{2k}$ = ratio 1:2

now

finding p

for this

$(m_1,m_2)=(1,2)$

For AB

$(x_1,y_1)=(1,8)$

$(x_2,y_2)=(4,2)$

now by using division formula

$(x,y)=(\frac{m_1x_2+m_2x_1}{m_1+m2},\frac{m_1y_2+m_2y_1}{m_1+m2})$

$=(\frac{1*4+2*1}{1+2},\frac{1*2+2*8}{1+2})=(2,6)$

similarly

Q divides AB

Ratio of AQ and QB = $\frac{2k}{1k}$ = ratio 2:1

$(x_1,y_1)=(1,8)$

$(x_2,y_2)=(4,2)$

$(m_1,m_2)=(2,1)$

by using division formula

$(a,b)=(\frac{m_1x_2+m_2x_1}{m_1+m2},\frac{m_1y_2+m_2y_1}{m_1+m2})$

$=(\frac{2*4+1*1}{2+1},\frac{2*2+1*8}{2+1})=(3,4)$

4 0

3 years ago

The equation of line p is y=ax+b. Which of these could be the equation of line q? A.y=−3a(x+6)+b

Ilia_Sergeevich [38]

The slope of line q is that of line p scaled by a factor of 3 (not -3). The y-intercept of line q is 6 less than the y-intercept of line p. The appropriate choice is
D. y = 3ax +b -6

7 0

3 years ago

Read 2 more answers

Find the Two Values that x can have if X^2 -10=26

Zolol [24]

Answer:

x1= -6 x2=6

Step-by-step explanation:

x^2-10 = 26

x^2 = 26 +10

x^2 = 36

x = sqrt(36)

x = -6 or x = 6 because both 6 and -6 squared are equal to 36

3 0

3 years ago

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The volume of a cone is 16 pi cubic inches. Its height is 12 inches. What is the radius of the cone? 2 in. 4 in. 12 in. 16 in.

mart [117]

The radius of cone is 2 inches

<em><u>Solution:</u></em>

<em><u>The volume of cone is given by formula:</u></em>

$V = \frac{\pi r^2h}{3}$

Where,

"V" is the volume of cone

"r" and "h" are the radius and height of cone respectively

Given that, volume of a cone is 16 pi cubic inches

Its height is 12 inches

Therefore, we get,

V = $16 \pi$ cubic inches

h = 12 inches

r = ?

<em><u>Substituting the values in formula, we get</u></em>

$16 \pi = \frac{ \pi \times r^2 \times 12}{3}\\\\16 = 4r^2\\\\r^2 = 4\\\\r = \pm 2$

Since, radius cannot be negative, ignore r = -2

Thus radius of cone is 2 inches

8 0

4 years ago

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