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Ratling [72]
3 years ago
12

Factor completely...........

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
3 0
6x² + 11x + 3 = (3x+1)(2x+3)

Hope that helps
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Wendell is looking over some data regarding the strength, measured in Pascals (Pa), of some building materials and how the stren
Slav-nsk [51]

The logarithmic model for the length when the strength is of 8 Pascals is given by:

  • f^{-1}(8) = \log_{2}{8} = \log_2{2^3} = 3
  • That is, the length is of 3 units.

<h3>What is the function?</h3>

The strength in Pascals for a building of length x is given by:

f(x) = 2^x

To find the length given the strength, we apply the inverse function, that is:

2^y = x

\log_{2}{2^y} = \log_2{x}

y = \log_2{x}

Hence, when the strength is of 8 Pascals, x = 8, and the length is given by:

f^{-1}(8) = \log_{2}{8} = \log_2{2^3} = 3

You can learn more about logarithmic functions at brainly.com/question/25537936

6 0
2 years ago
One teacher wants to give each student 7 over 9 of a slice of pizza. If the teacher has 7 slices of pizza, then how many student
Anna007 [38]
Total = 7 slices.
1student = 7/9 of a slice.

Total number of students:

7 \div  \dfrac{7}{9} 

= 7 \times  \dfrac{9}{7}

= 9

---------------------------------------------------------------------------
Answer: She will be able to hand out to 9 students.
---------------------------------------------------------------------------
3 0
2 years ago
Which of the following exponential equations could describe the graph shown below
snow_lady [41]
Since the line crosses the Y axis below 1 and raises going to the right it would be y=1/3(4)^x
6 0
3 years ago
Read 2 more answers
3. Which of the following quadratic equations has no solution? A) 0 = −2(x − 5)2 + 3 B) 0 = −2(x − 5)(x + 3) C) 0 = 2(x − 5)2 +
klemol [59]

Answer:

D) 0 = 2(x + 5)(x + 3)

Step-by-step explanation:

Which of the following quadratic equations has no solution?

We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.

A) 0 = −2(x − 5)2 + 3

0 = -2(x - 5) × 5

0 = (-2x + 10) × 5

0 = -10x + 50

10x = 50

x = 50/10

x = 5

Option A has a solution of 5

B) 0 = −2(x − 5)(x + 3)

Take each of the factors and equate them to zero

-2 = 0

= 0

x - 5 = 0

x = 5

x + 3 = 0

x = -3

Option B has a solution by one of its factors as a positive value of 5

C) 0 = 2(x − 5)2 + 3

0 = 2(x - 5) × 5

0 = (2x -10) × 5

0 = 10x -50

-10x = -50

x = -50/-10

x = 5

Option C has a solution of 5

D) 0 = 2(x + 5)(x + 3)

Take each of the factors and equate to zero

0 = 2

= 0

x + 5 = 0

x = -5

x + 3 = 0

x = -3

For option D, all the values of x are 0, or negative values of -5 and -3.

Therefore the Quadratic Equation for option D has no solution.

3 0
3 years ago
A bag contains 7 marbles, of which I is orange,
lyudmila [28]
6/7 because only one marble is orange
5 0
3 years ago
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