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Ksivusya [100]
3 years ago
10

Write the product in its simplest form -2b^3 (-b^9)

Mathematics
2 answers:
VashaNatasha [74]3 years ago
5 0
The Example is you only need a calculater for this and you get  -2 1/8 - (-6^9)
Flauer [41]3 years ago
4 0
-2b³ * -b⁹

2b³ ⁺ ⁹       - times - = +

2b¹²
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Do the following side lengths form a triangle?<br><br> 6, 18, 14
iren2701 [21]

Answer:

Yes

Step-by-step explanation:

Conditions for the sides to form a triangle is that sum of any two sides should be greater than the third side.

6 + 18 = 24

24 > 14

18 + 14 = 32

32 > 6

6 + 14 = 20

20 > 18

Therefore,

sides 6, 18 and 14 forms a triangle.

5 0
2 years ago
Help with this question Asap!! I need all the help I can get!
tankabanditka [31]

Answer:

\large{YES}\ \dfrac{BC}{YZ}=\dfrac{AC}{XY}=\dfrac{AB}{XZ}=\dfrac{2}{1}\\\\\text{and}\ \angle B\cong\angle Z,\ \angle C\cong\angle Y,\ \angle A\cong\angle X

Step-by-step explanation:

BC\to ZY\\AB\to XZ\\AC\to XY\\\angle A\to\angle X\\\angle B\to\angle Z\\\angle C\to\angle Y

\text{We have:}\\\\\triangle ABC:\ AB=20,\ BC=12,\ AC=18\\\triangle XZY:\ XZ=10,\ YZ=6,\ XY=9\\\\\text{check the ratio:}\\\\\dfrac{AB}{XZ}=\dfrac{20}{10}=2\\\\\dfrac{BC}{YZ}=\dfrac{12}{6}=2\\\\\dfrac{AC}{XY}=\dfrac{18}{9}=2\\\\\text{CORRECT :)}\\\\\angle B\cong\angle Z,\ \angle C\cong\angle Y\\\\\text{We know that: The sum of the acute angles in a right triangle is}\ 90^o.\\\\m\angle B+m\angle A=90^o\ \text{and}\ m\angle Z+m\angle X=90^o

\text{We know}\ m\angle B=m\angle Z\to \ m\angle A=m\angle X.\\\text{therefore}\ \angle A\cong\angle X

5 0
3 years ago
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pshichka [43]

Answer:

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Step-by-step explanation:

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7 0
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g

Step-by-step explanation:

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3 years ago
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OLga [1]
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7 0
3 years ago
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