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Ksivusya [100]
3 years ago
10

Write the product in its simplest form -2b^3 (-b^9)

Mathematics
2 answers:
VashaNatasha [74]3 years ago
5 0
The Example is you only need a calculater for this and you get  -2 1/8 - (-6^9)
Flauer [41]3 years ago
4 0
-2b³ * -b⁹

2b³ ⁺ ⁹       - times - = +

2b¹²
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I think it is 3:1 so tell me if it is wrong
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(2+0.4 + 0.6)² I have been stuck on this problem for a while
Anna11 [10]
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7 0
1 year ago
Suppose that the perimeter a rectangle is 54 feet, and the length is 13 feet more than the width. Find the width ractangle, in f
Vesnalui [34]

Answer:7feet

Step-by-step explanation:

perimeter(p)=54ft

Width(w) +13=Length(L)

Perimeter=2xLength+2xwidth

P=2xL+2xw

L=w+13

54=2(w+13)+2w

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Collect like terms

54-26=2w+2w

28=4w

Divide both sides by 4

28/4=4w/4

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8 0
4 years ago
The vertices of ABC are A(-3,5), B(-2,3), and C(-5,3). If ABC is reflected across the y-axis to produce the image A'B'C', find t
Nat2105 [25]

Answer:

C' =(5,3)

Step-by-step explanation:

Given

A = (-3,5)

B = (-2,3)

C = (-5,3)

Reflection across y-axis

Required

Find C'

For reflection across y-axis, the rule is:

(x,y) \to (-x,y)

So, the image of C is:

(-5,3) \to (-(-5),3)

(-5,3) \to (5,3)

Hence:

C' =(5,3)

7 0
3 years ago
Solve the system using elimination.<br><br> 2x + 3y = 17<br> x + 5y = 19
ale4655 [162]

\left\{\begin{array}{ccc}2x+3y=17\\x+5y=19&|\text{multiply both sides by (-2)}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+3y=17\\-2x-10y=-38\end{array}\right}\qquad\text{add both sides of equations}\\.\qquad\qquad-7y=-21\qquad\text{divide both sides by (-7)}\\.\qquad\qquad \boxed{y=3}\\\\\\\text{Substitute the value of y to the second equation}\\\\x+5(3)=19\\\\x=15=19\qquad\text{subtract 15 from both sides}\\\\\boxed{x=4}\\\\Answer:\ x=4\ and\ y=3.

5 0
3 years ago
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