Answer:
Wyzant
Question
Flying against the wind, an airplane travels 4200 km in 7 hours. Flying with the wind, the same plane travels 4000 km in 4 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer · 1 vote
Let Va = the velocity of the airplane Let Vw = the velocity of the wind When flying with the wind: (Va+Vw)*(4 hours) = 4000 4Va + 4Vw = 4000 4Vw = 4000 - 4Va Vw = 1000 - Va When flying against the wind: (Va-Vw)*(7 hours) = 4200 km7Va - 7Vw = 4200 Substitute 1000-Va for Vw and solve for Va: 7Va - 7(1000-Va) = 4200 7Va -7000 + 7Va = 4200 14Va = 11200 Va = 800 km/hr Rate of wind: Vw = 1000 - Va = 1000 - 800 = 200 km/hour
More
Socratic
Question
Flying against the wind, an airplane travels 4500 in 5 hours. Flying with the wind, the same plane travels 4640 in 4 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer · 0 votes
The speed of plane in still air is 1030 km/hr and wind
Step-by-step explanation:
Answer:
Step-by-step explanation:
In the given division, when 24.725 is divided by 215,
Step 1 is the wrong step.
Quotient in first step will be 0.1 .
Part C.
215) 24.725 (0.115
<u> 215</u>
322
<u>215</u>
1075
<u>1075</u>
0
Therefore, the correct way to divide should be as agove.
Quotient after division should be 0.115.
Answer:
5.525
Step-by-step explanation:
1. (7x^(2))/(2x + 6) -:(3x - 5) / (x + 3) Solve Bold
(7x^(2)) / (2x + 6) -:(3x - 5) / (x + 3)
2. 49x / 8x - (-2x) / 3x Solve Bold
49x/8x-(-2x)/3x
3. 6.125 - .6 Solve Bold
Answer: 5.525
No, because something extra is being added/divided and there are too many variables on one side
It's a lot like solving equations.
3b-7 < 32
Add 7 to each side.
3b < 39
Divide by 3 on each side.
b < 13
Hope this helps :)
