A - f(2x) B - 1/2f(x) C - f(1/2x) D - 2f(x)
1 answer:
Answer:
A:
Step-by-step explanation:
In this case it can be seen that the x values are being affected by this transformation. This means that we should look for points on f and g with the same y value but different x values. However in this case it is hard to pinpoint easy coordinates to work with. This is where process of elimination can help. We know it cant be B or C because if the dilation ratio is outside the function, the y values would be affected. That leaves it to A or D. We can see that g has shrunk from the original function. Shrinking along the x-values can be notated by the reciprocal of the factor of shrinking. In this case it looks like it shrunk down to half of the originals size. If we take the reciprocal of a half we get 2. Therefore if we plug that in we get:
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Using the formula of test statistic, the value of the test statistic is 2.6961.
The mean of the public accountant is
Mean x(p) =50.2+59.8+57.3+59.2+53.2+56.0+49.9+58.5+56.0+51.9/10
x(p) = 55.2
Now the standard deviation of public accountant is
SD(p) = √{∑(x-x(p))^2/n-1}
SD(p) = √(50.2-55.2)^2+(59.8-55.2)^2+..................+(51.9-55.2)^2/n-1
After solving;
SD(p) = 3.34
The mean of the financial planner is
Mean x(F) =48.0+49.2+53.1+55.9+51.9+53.6+49.7+53.9+52.8+48.9/10
x(F) = 51.6
Now the standard deviation of financial planner is
SD(F) = √{∑(x-x(p))^2/n-1}
SD(F) = √(48.0-51.6)^2+(49.2-51.6)^2+..................+(48.9-51.6)^2/n-1
After solving;
SD(F) = 2.57
Test Statistic (t) =
t =
After solving
t = 2.6961
Hence, the value of the test statistic is 2.6961.
To learn more about test statistic link is here
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The right question is
public accountant 50.2 59.8 57.3 59.2 53.2 56.0 49.9 58.5 56.0 51.9
financial planner 48.0 49.2 53.1 55.9 51.9 53.6 49.7 53.9 52.8 48.9
Use a 0.05 level of significance and test the hypothesis that there is no difference between the starting annual salaries of public accountants and financial planner
Find the value of the test statistic.