Answer:
(2x - 5 ) (3x^2 + 5x - 7) = 6x^3 - 5x^2 - 39x - 35
The product of 2x – 5 and 3x2 + 5x - 7equal to the product of 5x - 2 and 3x2 + 5x - 7 are not equal.
Step-by-step explanation:
Product means multiplication
Product of 2x - 5 and 3x^2 + 5x - 7
(2x - 5 ) (3x^2 + 5x - 7)
= 6x^3 + 10x^2 - 14x - 15x^2 - 25x - 35
Collect like terms
= 6x^3 + 10x^2 - 15x^2 - 14x - 25x - 35
= 6x^3 - 5x^2 - 39x - 35
Product of 5x - 2 and 3x^2 + 5x - 7
(5x - 2) (3x^2 + 5x - 7)
= 15x^3 + 25x^2 - 35x - 6x^2 - 10x + 14
Collect like terms
= 15x^3 + 25x^2 - 6x^2 - 35x - 10x + 14
= 15x^3 + 19x^2 - 45x + 14
The product of 2x – 5 and 3x^2 + 5x - 7equal to the product of 5x - 2 and 3x^2 + 5x - 7 are not equal.
They both consist of different variables in their multiplier
Answer: One book has a greater mass.
Step-by-step explanation:
Jamal has a pair of shoes with a total mass of 960 grams. This means that each shoe has a mass of:
960 grams ÷ 2= 480 grams per shoe.
Jamal also has four identical books with a total mass of 2 kilograms. Note that 1000 grams make a kilograms. Therefore 2 kilograms will be (2 × 1000 grams) = 2000 grams.
Each book will have a mass of:
2000 ÷ 4 = 500 grams per book.
One shoe has a mass of 960 divided 2 = 480 grams . One book has a mass of 2000 divided 4 = 500 grams . So one book has a greater mass.
The <em><u>correct answer</u></em> is:
D) Closed circle on 8, shading to the right.
Explanation:
First we must solve the inequality:
x - 3 ≥ 5
Add 3 to each side:
x - 3 + 3 ≥ 5 + 3
x ≥ 8
To graph this, we want a circle on 8 Since it is "greater than or equal to," 8 is included in the solution set. This means the circle will be closed.
Since it is "greater than," we want the numbers to the right of 8 on the number line.
This means the inequality will be a closed circle and shaded to the right.
3 = $9.81
1 = $?
To find this you have to do 9.81/3.
Hope this helps and have a nice day!!
Answer: Option C
Step-by-step explanation:
Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:
If 
then the graph of k(x) will be the graph of f(x) displaced vertically b units down.
If then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.
In this case we have
We know that this function has its vertex in point (0,0).
Then, to move its vertex 7 units down we apply the transformation:
.
Then the function k(x) that will have its vertex 7 units below f(x) is
