Well, it depends on the triangle and how big it is, if we dont know, there could be infinite possibilities
Answer:
m<PQR = 80°
Step-by-step explanation:
<u>Points to remember</u>
Sum angles in a linear pair is 180
<u>To find the value of x</u>
It is given that, angle PQR and angle RQS are linear pairs, and
m< PQR =5x+5 and m<RQS =11x-65
m<PQR + m<RQS = 180
5x + 5 + 11x - 65 = 180
16x -60 = 180
16x = 180 + 60
16x = 240
x = 15
<u>To find the value of angle PQR</u>
m<PQR = 5x + 5
= 5*15 + 5
= 75 + 5 = 80
Therefore m<PQR = 80°
Answer:
(B) 18 cm x 8 cm
Step-by-step explanation:
let the length be x,
then the width is 
x + 2
2( x + 2 + x ) = 52
x + 2 + x = 26
= 24
x = (24*3)/4
x = 18
then the length is 18 cm
and width is (1/3)*18 + 2 = 8
Therefore the dimensions are length:width = 18 cm : 8 cm
Answer:
t is 7
Step-by-step explanation:
i did it
Answer:
30 m/s
Step-by-step explanation:
Let's say the distance from the first car to the intersection is x, and the distance from the second car to the intersection is y.
The distance between the cars can be found with Pythagorean theorem:
d² = x² + y²
Taking derivative with respect to time:
2d dd/dt = 2x dx/dt + 2y dy/dt
d dd/dt = x dx/dt + y dy/dt
We know that x = 200, dx/dt = -25, y = 150, and dy/dt = -50/3.
To find dd/dt, we still need to find d.
d² = x² + y²
d² = (200)² + (150)²
d = 250
Plugging everything in:
250 dd/dt = (200) (-25) + (150) (-50/3)
dd/dt = -30
The cars are approaching each other at a rate of 30 m/s at that instant.
