Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
Answer:
All expressions are correct
Step-by-step explanation:
9z+7z = 16 z
We need to find an expression ( or expressions ) that are equal to 16z
6z+3z+ 7z = 16z Correct
z+8z+7z = 16z Correct
z*16 = 16z Correct
21z+ -5z = 16z Correct
For the a factor in a 1 and then do the problem once you find the product plug your a back in
Whats the question? or any specific information
Answer:
3g^2 (2g^6-g^2+3) the ^ symbole is means to the power
Step-by-step explanation:
