Express 140 as a product of its prime factors

Please answer this and put it in simplest form

Agata [3.3K]

you need to make the denominators that same and then you simply simplify the problem

9 4/12 = 9 1/3

8 0

3 years ago

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There are five seniors in a class. For each situation, write how the binomial formula is used to calculate the probability.

ololo11 [35]

A) The answer is 5.

nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things

There are five seniors in a class: n = 5
<span>I choose one senior: r = 1
</span>
nCr = n! / (r! (n - r)!)
5C1 = 5! / (1! (5 - 1)!)
= (5 * 4 * 3 * 2 * 1) / (1 * 4!)
= 120 / (4 * 3 * 2 * 1)
= 120 / 24
= 5

b) The answer is 10.

nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things

There are five seniors in a class: n = 5
I choose two seniors: r = 2

nCr = n! / (r! (n - r)!)
5C2 = 5! / (2! (5 - 2)!)
= (5 * 4 * 3 * 2 * 1) / ((2 * 1) * 3!)
= 120 / (2 * (3 * 2 * 1))
= 120 / (2 * 6)
= 120 / 12
= 10

c) The answer is 10.

nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things

There are five seniors in a class: n = 5
I choose three seniors: r = 3

nCr = n! / (r! (n - r)!)
5C3 = 5! / (3! (5 - 3)!)
= (5 * 4 * 3 * 2 * 1) / ((3 * 2 * 1) * 2!)
= 120 / (6 * (2 * 1))
= 120 / (6 * 2)
= 120 / 12
= 10

d) The answer is 5.

nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things

There are five seniors in a class: n = 5
I choose four seniors: r = 4

nCr = n! / (r! (n - r)!)
5C4 = 5! / (4! (5 - 4)!)
= (5 * 4 * 3 * 2 * 1) / ((4 * 3 * 2 * 1) * 1!)
= 120 / (24 * 1)
= 120 / 24
= 5

e) The answer is 1.

nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things

There are five seniors in a class: n = 5
I choose five seniors: r = 5

nCr = n! / (r! (n - r)!)
5C5 = 5! / (5! (5 - 5)!)
= (5 * 4 * 3 * 2 * 1) / ((5 * 4 * 3 * 2 * 1) * 1!)
= 120 / (120 * 1)
= 120 / 120
= 1

8 0

3 years ago

A diagonal of a cube measures StartRoot 294 EndRoot cm. The diagonal of a face measures 14 cm. What is the length of an edge of

hram777 [196]

The side of the edge of the cube is 9. 9cm

<h3>How to determine the length</h3>

Given that the diagonal of a cube measures the square root of 294cm and the diagonal of a face measures 14cm

To find the edge of the face, we know that the face of the cube is a square

Formula for diagonal of a square = $\sqrt{2a}$