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trapecia [35]
3 years ago
15

I need someone to tell me what to do in these, i have no clue how to get it.

Mathematics
1 answer:
Zanzabum3 years ago
3 0
To convert a decimal to a fraction, we simply "add as many zeros to the denominator as there are decimals, and lose the dot", what the dickens does that mean?

well, let's see, notice in this case, the radicand has 4 decimals, so we'll use 4 zeros to make it a fraction, and lose the dot,

\bf \pm\sqrt{0.0081}\\\\
-------------------------------\\\\
0.\underline{0081}\implies \cfrac{00081}{1\underline{0000}}\implies \cfrac{81}{10000}\implies \cfrac{9^2}{100^2}\\\\
-------------------------------\\\\
\pm\sqrt{\cfrac{9^2}{100^2}}\implies \pm\cfrac{\sqrt{9^2}}{\sqrt{100^2}}\implies \pm\cfrac{9}{100}



as for the other one

\bf 5x^2-21=39\implies 5x^2=60\implies x^2=\cfrac{60}{5}\implies x^2=12
\\\\\\
x=\pm\sqrt{12}\implies x=\pm\sqrt{4\cdot 3}\implies x=\pm\sqrt{2^2\cdot 3}\implies x=\pm 2\sqrt{3}
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(02.03 MC) The temperature at a mountain base camp was −2 degrees Celsius on Thursday. Friday morning, the temperature was 1 deg
aev [14]

Answer:

The temperature at the base camp Friday evening is - 6 degrees Celsius.

Step-by-step explanation:

To get the temperature at a mountain base camp on Friday evening, we must translate statement into a mathematical form:

(i) <em>The temperature at a moutain base camp was - 2 degress Celsius on Thursday</em>:

T_{o} = -2\,^{\circ}C

(ii) <em>Friday morning, the temperature was 1 degree Celsius lower than it was on Thursday</em>:

\Delta T_{1} = -1\,^{\circ}C

(iii) <em>Friday evening, the temperature was 3 degrees Celsius lower that it was that morning</em>:

\Delta T_{2} = -3\,^{\circ}C

The temperature at the base camp Friday evening is:

T = T_{o}+\Delta T_{1}+\Delta T_{2}

T = -2\,^{\circ}C-1\,^{\circ}C-3\,^{\circ}C

T = -6\,^{\circ}C

The temperature at the base camp Friday evening is - 6 degrees Celsius.

6 0
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