Answer:
1.41
Step-by-step explanation:
Given:
In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle.
To find:
The measures of the 2 acute angles of the triangle.
Solution:
Let x be the measure of one acute angle. Then the measure of another acute is (2x+12).
According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees. So,
Divide both sides by 3.
The measure of one acute angle is 26 degrees. So, the measure of another acute angle is:
Therefore, the measures of two acute angles are 26° and 64° respectively.
Answer:
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
6
2
−
5
−
4
=
0
6x^{2}-5x-4=0
6x2−5x−4=0
=
6
a={\color{#c92786}{6}}
a=6
=
−
5
b={\color{#e8710a}{-5}}
b=−5
=
−
4
c={\color{#129eaf}{-4}}
c=−4
=
−
(
−
5
)
±
(
−
5
)
2
−
4
⋅
6
(
−
4
)
√
2
⋅
6
Step-by-step explanation:
Answer:
$546000
Step-by-step explanation:
($65000×8%)(2)
You can solve this by cross multiplying. 20 ounces/$7=x ounces/$17. multiple $17 by 20 ounces and $7 by x ounces. (17x20=7x). 17x20=340, so 340=7x. Divide both sides by 7, and you will get x equals about 48.6.
