Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45
Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239
Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102
Solving for y,
y = -2(102) + 239
y = 35
Solving for z,
z = 102 - 45
z = 57
Idk how im supposed to answer this or whatevs bu
yes i have done factoring with variables.
distrubutive is the most involved in factoring method as i can tell.
i dont think ive studied this before or i mightve forgoten but im sure a polynomial can be factored into another one.
and yea. hope this helped in sum way
Answer:
144
Step-by-step explanation:
54+90=144
144-90=54
90+54=144
144-54=90
Answer:
Step-by-step explanation:
p+1 +8 = 8p+16
p+9 = 8p+16
9-16 = 8p-p
-7=7p
-7/7 =p
-1=p
Step-by-step explanation:
3(x+2)-(2x-1)=4(3-x)
3x+6-2x+1=12-4x
3x-2x+4x=12-6-1
5x=5
x=1