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4 years ago

Reduce your answer to its lowest term 2 1/5 + 5 4/5=

Mathematics

2 answers:

elena55 [62]4 years ago

6 0

Answer:

Step-by-step explanation:

First you make 2 1/5 11/5

then you make 5 4/5 29/5

then you add them 40/5

40/ 5 simplifiyed is 8

dimaraw [331]4 years ago

3 0

Answer:

Step-by-step explanation:

2 1/5 + 5 4/5 =

2 + 5 = 7

1/5 + 4/5 = 1

1 + 7 = 8

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Umnica [9.8K]

Answer:

Solve for b. by simplifying both sides of the inequality, then isolating the variable.

Inequality Form:

$b < -\frac{3}{7}$

Interval Notation:

( − ∞ , $-\frac{3}{7}$ )

Hope this helps :)

-ilovejiminssi♡

8 0

3 years ago

Justify each step in solving the equation 5(y+3)-11=-y-6 by writing a reason for each statement.

liubo4ka [24]

Explanation:

5(y+3)-11=-y-6 Given

5(y+3)=-y+5 . . . . addition property of equality (11 is added)

5y+15=y+5 . . . . . distributive property (5 is distributed)

5y=-y-10 . . . . . . . addition property of equality (-15 is added)

6y=-10 . . . . . . . . . addition property of equality (y is added)

y=-5/3 Division Property of Equality/Reduce

6 0

3 years ago

If (2i/2+i)-(3i/3+i)=a+bi, then b=

max2010maxim [7]

Answer:

b = -1/10.

Step-by-step explanation:

(2i/2+i)-(3i/3+i)

= 2i(3 + i) - 3i(2 + i) / (2 + i)(3 + i)

= 6i + 2i^2 - 6i - 3i^2 / (2 + i)(3 + i)

= (-2 + 3) / (6 + 5i - 1)

= 1 / (5 + 5i)

Now we multiply top and bottom by 5 - 5i :

= 5 - 5i / (5 + 5i)(5 - 5i)

= 5 - 5i / 25 -25i^2

= 5 - 5i / 50

= 1/10 - 1/10i

6 0

3 years ago

(CO 3) A survey indicates that shoppers spend an average of 22 minutes with a standard deviation of 8 minutes in your store and

padilas [110]

Answer: 0.60

Step-by-step explanation:

Given: Mean : $\mu = 22\text{ minutes}$

Standard deviation : $\sigma = 8\text{ minutes}$

The formula to calculate z is given by :-

$z=\dfrac{x-\mu}{\sigma}$

For x= 20 minutes

$z=\dfrac{22-20}{8}=0.25$

The P Value = $P(z$

Hence, the probability that a randomly selected shopper will spend less than 20 minutes in the store= 0.60

5 0

4 years ago

Find the approximate area between the curve f(x) = -4x² + 32x and on the x-axis on the interval [0,8] using 4 rectangles. Use th

Doss [256]

Split up the interval [0, 8] into 4 equally spaced subintervals:

[0, 2], [2, 4], [4, 6], [6, 8]

Take the right endpoints, which form the arithmetic sequence

$r_i=2+\dfrac{8-0}4(i-1)=2i$

where 1 ≤ i ≤ 4.

Find the values of the function at these endpoints:

$f(r_i)=-4{r_i}^2+32r_i=-16i^2+64i$

The area is given approximately by the Riemann sum,

$\displaystyle\int_0^8f(x)\,\mathrm dx\approx\sum_{i=1}^4f(r_i)\Delta x_i$

where $\Delta x_i=\frac{8-0}4=2$ ; so the area is approximately

$\displaystyle2\sum_{i=1}^4(-16i^2+64i)=-32\sum_{i=1}^4i^2+128\sum_{i=1}^4i=-32\cdot\frac{4\cdot5\cdot9}6+128\cdot\frac{4\cdot5}2=\boxed{320}$

where we use the formulas,

$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$

6 0

3 years ago

Reduce your answer to its lowest term 2 1/5 + 5 4/5=​

Reduce your answer to its lowest term 2 1/5 + 5 4/5=