<span>Here's the formula to find the area of a triangular prism: </span>
Now, let's define the variables.
b (base) = 3.6 mm
h (height) = 2.4 mm
l (length) = 5 mm
s (side length) = 3 mm
Next, plug the values in for the variables in the formula and solve.
Answer: the surface area is
56.64 millimeters
hope this helps! ps, I labeled a diagram for you
Option A
The line is perpendicular to
<u>Solution:</u>
Given that line is
We have to find the line perpendicular to this line.
The given line equation is in form of slope-intercept form
<em><u>The slope-intercept form is given as:</u></em>
y = mx + c
Where "m" is the slope of the line and "c" is the y-intercept
On comparing the given equation with slope-intercept form, we get
<em>If a line is perpendicular to another line, then the product of their slopes will always be -1</em>
Let the slope of line which is perpendicular to given line be "a"
Then we get,
Now look at the options and compare with slope intercept form and find out which option has the slope "m" =
Option A has the slope
Thus option A is correct
Answer:
S(0, 2)
Step-by-step explanation:
Midpoint Formula:
Step 1: Plug in known variables
5 = (10 + x)/2
-8 = (18 + y)/2
Step 2: Solve
10 = 10 + x
x = 0
-16 = 18 + y
y = 2
Step 3: Write coordinates
(0, 2)
Jk l k kno k no j kk knock ok no ok ok ok on k kno k on l ik ok kk on jk boo-boo
Answer: 23.7 lb
Step-by-step explanation:
Mean m = 15 lb
Standard deviation d = 3.3 lb
To determine the surcharge weight, we need to know the highest weight of 99% of the parcels.
P(z<x) = 0.99 = ¢(Z)
Z = 2.33
Since Z = (x - m)/d
x = dZ + m
x = 3.3*2.33 + 15
x = 22.689 lb approximately
x = 22.7 lb
Therefore, the highest weight for 99% if the parcels is 22.7 lb.
That is, the surcharge weight = 22.7 + 1 = 23.7 lb