Ask question

Ask question

All categories

Dennis_Churaev [7]

3 years ago

8

Which expression is equivalent to StartRoot StartFraction 2 x Superscript 5 Baseline Over 18 EndFraction EndRoot? Assume x great

er-than-or-equal-to 0. StartFraction x squared StartRoot x EndRoot Over 3 EndFraction StartFraction 3 StartRoot x EndRoot Over x squared EndFraction StartFraction StartRoot x EndRoot Over 3 x squared EndFraction StartFraction 2 x StartRoot x EndRoot Over 3 EndFraction

2 answers:

german3 years ago

6 0

Answer:

A. $\frac{x^2\sqrt{x}}{3}$

Step-by-step explanation:

We have been given an expression $\sqrt{\frac{2x^5}{18}}$ . We are asked to find which expression is equivalent to our given expression.

Let me simplify our given expression. First of all we will divide 18 by 2 as:

$\sqrt{\frac{2x^5}{2\cdot 9}}$

$\sqrt{\frac{x^5}{9}}$

Now we will rewrite $x^5 \text{ as } x^4\cdot x$ .

$\sqrt{\frac{x^4\cdot x}{9}}$

Now we will write $x^4\text{ and } 9$ as perfect squares.

$\sqrt{\frac{(x^2)^2\cdot x}{3^2}}$

Let us factor our perfect square from square-root.

$\frac{x^2\sqrt{x}}{3}$

Therefore, option A is the correct choice.

Elodia [21]3 years ago

5 0

Answer:

it's A on edge

Step-by-step explanation:

You might be interested in

-4.8f+6.4=-8.48 what's f 7.3y-5.18=-51.9 what's y

stich3 [128]

F=4 and y=3 those are the answers

8 0

3 years ago

light travels at 3x10 to the power of 8 meters per second. there are 8.64x10 to the power of 4 seconds in 24 hours. how many met

Vaselesa [24]

Distance = velocity * time

= 3 * 10^8 * 8.64 * 10^4

= 2.592 * 10^13 meters (answer)

6 0

3 years ago

Convert to scientific notation: 0.0509.

fomenos

Answer:

5.09 × 10^-2

Step-by-step explanation:

You have to take the number go to the decimal and move it until you get to the first number and in this case, it is 5 put the decimal there. To write it you have to count the number of times you moved the decimal. when doing this it will always be a number times 10^ the number you moved the decimal.

5 0

3 years ago

An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individ

Tema [17]

Answer:

a) P=0.558

b) P=0.021

Step-by-step explanation:

We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.

The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

$P(x=k)=\frac{\lambda^ke^{-\lambda}}{k!} =\frac{4^ke^{-4}}{k!}$

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:

$P(4\leq x\leq 9)=\sum_{k=4}^9P(k)\\\\\\ P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\P(9)=4^{9} \cdot e^{-4}/9!=262144*0.0183/362880=0.013\\\\\\$

$P(4\leq x\leq 9)=\sum_{k=4}^9P(k)=0.195+0.156+0.104+0.060+0.030+0.013=0.558$

b) The approximate probability that at least 9 carry the gene is:

$P(x\geq9)=1-P(x\leq 8)\\\\\\$

$P(0)=4^{0} \cdot e^{-4}/0!=1*0.0183/1=0.018\\\\P(1)=4^{1} \cdot e^{-4}/1!=4*0.0183/1=0.073\\\\P(2)=4^{2} \cdot e^{-4}/2!=16*0.0183/2=0.147\\\\P(3)=4^{3} \cdot e^{-4}/3!=64*0.0183/6=0.195\\\\P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\$

$P(x\geq9)=1-P(x\leq 8)\\\\P(x\geq9)=1-(0.018+0.073+0.147+0.195+0.195+0.156+0.104+0.060+0.030)\\\\P(x\geq9)=1-0.979=0.021$

8 0

3 years ago

13. Given f(x) = X – 3 and g(x) = 4x, find f(g(x)).

Blizzard [7]

Step-by-step explanation:

f(g(x))

= f(4x)

= (4x) - 3. (A)

4 0

3 years ago

Read 2 more answers