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motikmotik
3 years ago
8

You were driving your car to UTD at a speed of 35 miles per hour. You stopped at the FloydCampbell intersection with the signal

light showing red (wavelength = 6.45 × 10–5 cm). After 30 sec, the signal becomes green whose frequency is 5.80 × 1014 s –1 . Which light has higher energy?
Physics
1 answer:
ser-zykov [4K]3 years ago
8 0

Answer:

green light have high energy

Explanation:

We have given the wavelength of the red light \lambda =6.45\times 10^{-5}cm=6.45\times 10^{-7}m

Speed of the light c=3\times 106{8}m/sec

The energy of the signal is given by E=h\nu =h\frac{c}{\lambda }=\frac{6.67\times 10^{-34}\times 3\times 10^{8}}{6.45\times 10^{-7}}=3.1023\times 10^{-15}j

The frequency of the green light is given by:

f=5.80\times 10^{14}s^{-1}

So energy E=h\nu =6.67\times 10^{-34}\times 5.80\times 10^{14}=3.8686\times 10^{-19}j

So green light have high energy

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One small speaker is placed 3m to the east of a second speaker, and a listener stands 4m directly south of one of the speakers.
alexandr402 [8]

Answer:

The value is \lambda  =  2 \  m

Explanation:

From the question we are told that

     The distance of the speaker  from the  second speaker  to the east is  d = 3 \  m

      The distance of the speaker  from the listener  to the south is     a = 4 \  m

Generally given that if the speaker move in any direction, their sound become  louder , it then mean that the position of the listener of minimum sound (i.e a position of minima ) ,

Generally the path difference of the sound produce by both speaker at a position of minima is mathematically represented as

              y =  \frac{\lambda}{2}

Generally considering the orientation  of the speakers and applying Pythagoras theorem we see that  distance from the second speaker to the listener  is mathematically represented as

             b =  \sqrt{d^ 2 + a^2 }

=>           b =  \sqrt{3^ 2 + 4^2 }

=>           b = 5

Generally the path difference between the two speaker with respect to the  listener is  

              y =  b - a

=>           y = 5 - 4

=>           y = 1

So  

              1 =  \frac{\lambda}{2}

=>           \lambda  =  2 \  m

4 0
3 years ago
An open bed truck is moving at 20 m/s and comes to a stop. A 100 kg crate sitting in the back of the truck remains at rest in th
zzz [600]

The work done was done by friction to keep the crate from moving as the truck came to a stop is 20,000 J.

<h3>Work done by friction to prevent the crate from moving</h3>

The work done is determined by applying the principle of conservation of energy.

W = K.E

W = ¹/₂mv²

where;

  • m is mass of crate
  • v is speed of the crate with respect to the truck = 20 m/s

W = ¹/₂(100)(20²)

W = 20,000 J

Thus, the work done was done by friction to keep the crate from moving as the truck came to a stop is 20,000 J.

Learn more about work done here: brainly.com/question/8119756

#SPJ1

3 0
2 years ago
A satellite is launched to orbit the Earth at an altitude of 2.90 x10^7 m for use in the Global Positioning System (GPS). Take t
marin [14]

Answer:

T=66262.4s

Explanation:

From the question we are told that:

Altitude A=2.90 *10^7

Mass m=5.97 * 10^{24} kg

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Generally the equation for Satellite Speed is mathematically given by

V=(\frac{GM}{d} )^{0.5}

V=(\frac{6.67*10^{-11}*5.97 * 10^{24}}{6.38 *10^6+2.90 *10^7} )^{0.5}

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Period T is Given as

T=\frac{2 \pi *a}{V}

T=\frac{2 \pi *(6.38 *10^6+2.90 *10^7}{3354.83}

T=66262.4s

4 0
3 years ago
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