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4 years ago

Nl

Physics

1 answer:

Sedaia [141]4 years ago

6 0

Answer:

10 mL= 0.01 L

Explanation:

V(water) = 20 mL

V(water + a marble) = 30 mL

V(marble) = V(water + a marble) - V(water) = 30 mL - 20 mL = 10 mL= 0.01 L

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What services do plants provide? Select the three that apply.

Irina18 [472]

The answer to this is B, C, and D. hope this helped

6 0

3 years ago

Objects P and Q are placed in a bowl of water. P floats and Q sinks. Which one or more of the following can be deduced from this

Lady bird [3.3K]

The correct option that can be deduced for both Object P and Q is Option b) I and II only

To solve this question correctly, we need to understand the concept of density and it relation to mass and volume.

<h3>What is Density?</h3>

Density is a physical property of an object and can be expressed by using the relation:

$\mathbf{Density = \dfrac{mass}{volume}}$

From the given parameters, we are being told that:

P → floats
Q → sinks

This implies that Q has a greater density that P. Since Q has a greater density than P, Q will be heavier since it will have greater mass.

However, Q will not be denser than water because if that happens, P will be have a greater density which is untrue in this scenario.

Therefore, we can conclude that:

1. Q is heavier than P
II. 1cm³ of Q has a greater mass than 1cm³ of P

Learn more about density here:

brainly.com/question/6838128

6 0

3 years ago

The material or substance that a wave moves through is called a ____

pshichka [43]

1. medium
2. Type
3. Temperature

Just took the quiz

7 0

3 years ago

Read 2 more answers

Question 4 (18 marks) (a) During a Physics Lab experiment, 1 st year SFY students analyzed the behavior of capacitors by connect

Nataly_w [17]

Answer:

1.) 274.5v

2.) 206.8v

Explanation:

1.) Given that In one part of the lab activities, students connected a 2.50 µF capacitor to a 746 V power source, whilst connected a second 6.80 µF capacitor to a 562 V source.

The potential difference and charge across EACH capacitor will be

V = Voe

Where Vo = initial voltage

e = natural logarithm = 2.718

For the first capacitor 2.50 µF,

V = Vo × 2.718

746 = Vo × 2.718

Vo = 746/2.718

Vo = 274.5v

To calculate the charge, use the below formula.

Q = CV

Q = 2.5 × 10^-6 × 274.5

Q = 6.86 × 10^-4 C

For the second capacitor 6.80 µF

V = Voe

562 = Vo × 2.718

Vo = 562/2.718

Vo = 206.77v

The charge on it will be

Q = CV

Q = 6.8 × 10^-6 × 206.77

Q = 1.41 × 10^-3 C

B.) Using the formula V = Voe again

165 = Vo × 2.718

Vo = 165 /2.718

Vo = 60.71v

Q = C × 60.71

Q = C

4 0

3 years ago

ENERGY SAVERS RACE, BRAIN BURNER. This question is about solar cars at the Chuck Norris Institute of Technology, CNIT, in Ocala,

Hunter-Best [27]

Answer:

a) d = 6.0 m

Explanation:

Since car is accelerating at uniform rate then here we can say that the distance moved by the car with uniform acceleration is given as

$d = \frac{(v_f + v_i)}{2} \times t$

here we know that

$v_f = 10 m/s$

$v_i = 0$

$t = 1.2 s$

now we will have

$d = \frac{(10 + 0)}{2}\times 1.2$

$d = 5 \times 1.2$

$d = 6.0 m$

4 0

3 years ago