Answer:
The least number of forces required to stretch a spring is one.
Explanation:
Let suppose that spring is ideal, that is, that effects from its mass can be neglected since it is insignificant in comparison with external forces. In addition, let the spring have a linear behavior, meaning that net external longitudinal force exerted on spring is directly proportional to defomation. (Hooke's Law) That is:
(1)
(2)
Where:
- Net external force, measured in newtons.
- Spring constant, measured in newtons per meter.
- Deformation of spring, measured in meters.
Hence, the least number of forces required to stretch a spring is one.
Answer:The speed is 54 mm/s, the units are mm/s.
Explanation:
1) Data:
a) λ = 6mm
b) f = 9 Hz = 9 s⁻¹
c) v = ?
2) Formula:
wave equation: v = f × λ
3) Solution:
v = 9 s⁻¹ × 6mm
v = 54 mm/s
The speed is 54 mm/s, the units are mm/s.
Answer:
Option B. quantum mechanics
Explanation:
Quantum Mechanics, at atomic and sub-atomic levels deal with the study of how particles at this level behave and how the matter and energy interacts.
It also explains the properties of atoms, molecules and the particles constituting these.
The wave- particle duality of quantum mechanics that says that matter or every quantum of it exhibits wave as well as particle nature.
This theory was incorporated with its mathematical description given by Schrodinger was also incorporated in the theory for eave-particle duality and The probability for the existence of particle was determined.
The elastic potential energy in the spring is 1 J
Explanation:
The elastic potential energy stored in a spring is given by:
where
k is the spring constant
x is the stretching/compression of the spring with respect to the unstretched length
For the spring in this problem, we have:
k = 200 N/m is its spring constant
The spring is stretched by 5.0 cm first and then by an additional 5.0 cm, so the total stretching is
Therefore, the elastic potential energy in the spring is:
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