¡Hellow!
For this problem, first, lets convert the seconds in hours:
5,4x10³
5400
h = sec / 3600
h = 5400 s / 3600
h = 1,5
Let's recabe information:
d (Distance) = 386 km
t (Time) = 1,5 h
v (Velocity) = ?
For calculate velocity, let's applicate formula:

Reeplace according we information:
386 km = v * 1,5 h
v = 386 km / 1,5 h
v = 257,33 km/h
The velocity of the train is of <u>257,33 kilometers for hour.</u>
<u></u>
Extra:
For convert km/h to m/s, we divide the velocity of km/h for 3,6:
m/s = km/h / 3,6
Let's reeplace:
m/s = 257,33 km/h / 3,6
m/s = 71,48
¿Good Luck?
The electric field of a charged object will be strongest when all the field lines are close to one another.
beacsue, the strength of electric field depends on the number of lines of electric field. More lines at a place, higher the electric field strength. Thus, any charge in that area will face more electric field.
Answer:
B. to the right
Explanation:
Given:
- distance of the test charge from +Q, r
- distance of test charge from +2Q, 2r
<u>Force on the test charge due to +Q:</u>

<u>Force on the test charge due to +Q:</u>

Since all the charges are positive here, so they will try to repel the test charge away. And the force due to charge +Q will be greater so initially the test charge will move rightwards away from the +Q charge.
Answer:
The caterpillar had to move across the horizontal segments. I hope this helps :)
Explanation: