Answer:
I really don't know that 100% a question. But, Your answer will be C. Use the first command group under the Home tab to open a dialog box. Because, You got to use the first command group under screen computer. Then, You got use the click the help icon button that appears infront of the right interface. After that, If it shows a ok button press ok.
Um, Hope That Helps!!~
By Itsbrazts
a crown Source because is beautiful in its own way and it'll be a nice company because you can own the company in a beautiful way now will people wakes blow and now there is not a company that's named the same thing and over and over again
Answer:
public static int greaterThanInt(int n){
return n+10;
}
Explanation:
This is a very simple method in Java. it will accept an argument which is an integer n and return n+10 since the question requires that an arbitrary integer greater than n be returned adding any int value to n will make it greater than n.
A complete java program calling the method is given below:
<em>import java.util.Scanner;</em>
<em>public class ANot {</em>
<em> public static void main(String[] args) {</em>
<em> Scanner in = new Scanner(System.in);</em>
<em> System.out.println("Please enter an integer");</em>
<em> int n = in.nextInt();</em>
<em> int greaterInt = greaterThanInt(n);</em>
<em> System.out.println("You entered "+n+", "+greaterInt+" is larger than it");</em>
<em> }</em>
<em> public static int greaterThanInt(int n){</em>
<em> return n+10;</em>
<em> }</em>
<em>}</em>
Automobile repair shops produce many types of waste -- some hazardous, some not necessarily hazardous but still potentially damaging to the environment if not handled properly, and all requiring proper treatment and/or disposal at significant cost to the business. A list of the types of waste that the shop owner or manager must contend with would include:
solvents (paints and paint thinners)
antifreeze
scrap metal
batteries and other auto parts
oils and oil filters
fuels of various types
acids and alkalis (contaminated rags and towels)
Whatever the nature and characteristics of the waste may be, it all has one thing in common: All waste represents loss of resources and loss of money.
Answer:
weights = []
total = 0
max = 0
for i in range(5):
weight = float(input("Enter weight " + str(i+1) + ": "))
weights.append(weight)
total += weights[i]
if weights[i] > max:
max = weights[i]
average = total / 5
print("Your entered: " + str(weights))
print("Total weight: " + str(total))
print("Average weight: " + str(average))
print("Max weight: " + str(max))
Explanation:
Initialize the variables
Create a for loop that iterates 5 times
Get the values from the user
Put them inside the array
Calculate the total by adding each value to the total
Calculate the max value by comparing each value
When the loop is done, find the average - divide the total by 5
Print the results
