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Pepsi [2]
2 years ago
5

Which of the following protects against cave-ins? A. All answer choices protect against cave-ins B. Shielding C. Shoring D. Slop

ing
Computers and Technology
2 answers:
Katarina [22]2 years ago
7 0

Answer: A) All answer choices protect against cave-ins

Explanation: Cave-in is the situation relating with collapse action of walls, boundaries, etc of any infrastructure ,roof, building etc.  The main methods used for prevention of cave-in situation are sloping shielding and shoring.

Sloping is the method in which prevents the sloping back of elements of site while experiencing high pressure. Shielding is the form of covering that is obtained by using trench boxes or other element for the support to act as shield .

Shoring is the technique in which prevention of cave-in is done through hiring aluminum hydraulic and related supporting components so that cave-ins can be stopped. Thus, all the options are correct.

babunello [35]2 years ago
4 0
I think it is b idk if it is 100% right
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Modify the list according to the following: append the smallest value at the end of the list when all numbers in the list are ne
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The solution code is written in Python 3:

  1. def modifyList(listNumber):
  2.    posCount = 0
  3.    negCount = 0
  4.    for x in listNumber:
  5.        if x > 0:
  6.            posCount += 1
  7.        else:
  8.            negCount += 1
  9.    
  10.    if(posCount == len(listNumber)):
  11.        listNumber.append(max(listNumber))
  12.    
  13.    if(negCount == len(listNumber)):
  14.        listNumber.append(min(listNumber))
  15.    
  16.    print(listNumber)
  17. modifyList([-1,-99,-81])
  18. modifyList([1,99,8])
  19. modifyList([-1,99,-81])

Explanation:

The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).

To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).

If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).

If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.

At last we can print the listNumber (Line 17).

If we test our function using the three sets of input list, we shall get the following results:

[-1, -99, -81, -99]

[1, 99, 8, 99]

[-1, 99, -81]

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3 years ago
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