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Lina20 [59]
3 years ago
5

Why do you want to work for Rev?

Computers and Technology
1 answer:
raketka [301]3 years ago
7 0

People do have reasons why they want to work for a particular company. It may be due to what they company stands for, what they make or about your dream.

I can therefore say that I want to work for Rev because they are revolutionizing the industry and I want to be part of the change process.

<h3>How do you answer why do you want to work?</h3>

Note that when looking for a job, job experience do matter. When ask the reason for looking for this job.

One can answer that they have the experience or the needed expertise and skills required for this job as they want to be aligned with what the company stands for.

Learn more about work  from

brainly.com/question/25573309

You might be interested in
In C++ please (read the image below for instructions)
FromTheMoon [43]

Using the knowledge in computational language in C code  it is possible to write a code that  print the month name along with their rainfall inches. Then we have to calculate the total rainfall.

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using </em><em>namespace </em><em>std;</em>

<em />

<em>// function to print the rainfall of each month</em>

<em>void rainfallStatistics(string month[], double rainfall[]){</em>

<em>    </em>

<em>    double sum = 0; // variable to store the total sum of rainfall</em>

<em>    string maxMonth = month[0]; // variable to return month with maximum rainfall</em>

<em>    double </em><em>maxRainfall </em><em>= INT_MIN; // variable to store the maximum rainfall</em>

<em>    </em>

<em>    // running the loop till the last month</em>

<em>    for(int i=0; i<12; i++){</em>

<em>        </em>

<em>        // printing the month and rainfall</em>

<em>        cout<< month[i] << "           " << fixed << setprecision(2) << rainfall[i] << " inches" << endl;</em>

<em>        </em>

<em>        // storing the sum</em>

<em>        sum = sum + rainfall[i];</em>

<em>        </em>

<em>        // checking the month with highest rainfall</em>

<em>        if(rainfall[i] > </em><em>maxRainfall</em><em>){</em>

<em>            </em>

<em>            maxRainfall = rainfall[i];</em>

<em>            maxMonth = month[i];</em>

<em>        }</em>

<em>    }</em>

<em>    </em>

<em>    // calculating the average of the rainfall</em>

<em>    double average = sum / double(12);</em>

<em>    </em>

<em>    cout << endl;</em>

<em>    cout << "Total for the year " << sum << " inches" << endl;</em>

<em>    cout << "Average rainfall per month " << average << " inches" << endl;</em>

<em>    cout << "Month with the greatest rainfall was " << maxMonth << " with rainfall of " << </em><em>maxRainfall </em><em><< " inches" << endl;</em>

<em>    </em>

<em>}</em>

<em>// driver program</em>

<em>int main()</em>

<em>{</em>

<em>    // array to store the nonth name</em>

<em>    string month[12] = {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"};</em>

<em>    </em>

<em>    // array to store the rainfall</em>

<em>    double rainfall1[12] = { 4.50, 4.25, 3.26, 1.35, 0.80, 0.20, 0.10, 0.00, 0.40, 1.20, 2.96, 4.71 };</em>

<em>    double rainfall2[12] = { 3.50, 1.25, 7.26, 8.35, 2.80, 0.00, 1.10, 4.00, 9.40, 2.20, 3.96, 4.71 };</em>

<em>    </em>

<em>    cout << "Hayward Statistics" << endl;</em>

<em>    cout << endl;</em>

<em>    cout<< "Month" << "         " << "Rainfall" << endl;</em>

<em>    </em>

<em>    // calling the function for Hayward</em>

<em>    </em><em>rainfallStatistics</em><em>(month, rainfall1);</em>

<em>    cout << endl;</em>

<em>    cout << endl;</em>

<em>    </em>

<em>    cout << "Houston Statistics" << endl;</em>

<em>    cout << endl;</em>

<em>    cout<< "Month" << "         " << "Rainfall" << endl;</em>

<em>    </em>

<em>    // calling the function for Houston</em>

<em>    rainfallStatistics(month, rainfall2);</em>

<em>    </em>

<em>    return 0;</em>

<em>}</em>

See more about c code at brainly.com/question/19705654

#SPJ1

8 0
1 year ago
Does the estimate of a tolerance level of 68.26% of all patient waiting times provide evidence that at least two-thirds of all p
ivanzaharov [21]

Answer:

Yes, because the upper limit is less Than 8 minutes

Explanation:

According to the empirical formula :

68.26% of data lies within 1 standard deviation from the mean;

Hence,

Mean ± 1(standard deviation)

The sample mean and sample standard deviation of the given data is :

Sample mean, xbar = Σx / n = 546 / 100 = 5.46

Sample standard deviation, s = 2.475 (Calculator)

The interval which lies within 68.26% (1 standard deviation is) ;

Lower = (5.460 - 2.475) = 2.985

Upper = (5.460 + 2.475) = 7.935

(2.985 ; 7.935)

Since the interval falls within ; (2.985 ; 7.935) whose upper level is less than 8 means patients will have to wait less Than 8 minutes.

8 0
3 years ago
Question 1 of 10
ycow [4]

Answer:

Explanation:

Def f

4 0
3 years ago
Which subscription service complements App-ID by enabling you to configure the next-generation firewall to identify and control
Nataly [62]

The subscription service that complements App-ID by enabling you to configure the firewall to identify and control access to websites is  URL Filtering.

<h3>What is URL filtering?</h3>

The term URL filtering is known to function by looking at the similarities of all web traffic against a given URL filters.

Note that it is one that is made up of database of sites that users do access and as such, the subscription service that complements App-ID by enabling you to configure the firewall to identify and control access to websites is  URL Filtering.

Learn more about subscription from

brainly.com/question/14073216

#SPJ1

4 0
3 years ago
In Windows Vista, which location contains the Printer link?
ipn [44]
I believe it's B.) Printer and Faxes.
3 0
4 years ago
Read 2 more answers
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