For a trapezoid, the area is:
S=(b+B)h/2, where b and B are the bases, and h is the height.
b=2
B=2+2+2=6
h=2.
S=(2+6)×2/2=8
Several examples of side lengths that are Pythagorean triples are the following with the corresponding side lengths A, B, C:
(5, 12, 13), (7, 24, 25), (3, 4, 5)
-E :)
Answer:
Step-by-step explanation:
Volume = 198 ft
length * width * height = 198
(x - 1) * (x + 4) * 3 = 198
(x - 1) * (x + 4) = 198/3
(x - 1) * (x + 4) = 66
x*x + x*4 -1*x - 1*4 = 66 {Use FOIL method to multiply}
x² + 4x - x - 4 = 66
x² + 3x - 4 =66
x² + 3x - 4 - 66 = 0
x² + 3x - 70 = 0
Now factorize.
x² + 10x - 7x - 7*10 = 0
x(x +10) - 7(x + 10 ) = 0
(x + 10)(x - 7) = 0
x - 7 = 0 {x + 10 is ignored because measurement cannot be in negative}
x = 7
length = x - 1 = 7 - 1 = 6ft
Width = x + 4 = 7 + 4 = 11 ft
