Vertex form is y=a(x-h)^2+k, so we can rearrange to that form...
y=3x^2-6x+2 subtract 2 from both sides
y-2=3x^2-6x divide both sides by 3
(y-2)/3=x^2-2x, halve the linear coefficient, square it, add it to both sides...in this case: (-2/2)^2=1 so
(y-2)/3+1=x^2-2x+1 now the right side is a perfect square
(y-2+3)/3=(x-1)^2
(y+1)/3=(x-1)^2 multiply both sides by 3
y+1=3(x-1)^2 subtract 1 from both sides
y=3(x-1)^2-1 so the vertex is:
(1, -1)
...
Now if you'd like you can commit to memory the vertex point for any parabola so you don't have to do the calculations like what we did above. The vertex of any quadratic (parabola), ax^2+bx+c is:
x= -b/(2a), y= (4ac-b^2)/(4a)
Then you will always be able to do a quick calculation of the vertex :)
Answer:
B. 434
Step-by-step explanation:
sorry for the late response! it’s 434. I worked out the problem & took the test, B is the correct answer.
Answer:
Step-by-step explanation:
This is a 30-60-90 triangle.
It's good to remember this. The side length opposite to the 60 degree angle is always the base multiplied by 
The length of the box would be 12288.
Answer:
Step-by-step explanation:
Let
n -----> number of tickets
C ----> represent the cost of buy n tickets online
we have the ordered pairs
(1,16.50) and (2,30.50)
<em>Find out the slope of the linear equation</em>
The formula to calculate the slope between two points is equal to
substitute the values
<em>Find the equation of the line in slope intercept form</em>
we have
substitute
substitute
The domain of the function is all positive integers (whole numbers) including zero
{0,1,2,3,4,...}
