Step-by-step explanation:
after I answered the other one(s), you should be really able to do this yourself.
it is precisely the same method and formula just with different numbers.
what's the problem now ?
y = -16x² + 247x + 141
we assume, the ground is at 0 ft.
so, we need to solve
0 = -16x² + 247 x + 141
the general solution for such quadratic equations is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = -16
b = 247
c = 141
x = (-247 ± sqrt(247² - 4×-16×141))/(2×-16) =
= (-247 ± sqrt(61009 + 9024))/-32 =
= (-247 ± sqrt(70033))/-32
x1 = (-247 + 264.6374879...)/-32 = -0.551171497... s
x2 = (-247 - 264.6374879...)/-32 = 15.9886715... s
again, the negative solution for time did not make any sense, so, x2 is our solution.
the rocket will hit the ground after about 15.99 seconds.
Answer:
if you're looking for x its -13
<span>Given that one
hundred students are asked a survey question as they walk through the
front gate at their middle school.
This a representative sample of
the schools population because the sampling is random and is not biased.</span>
To find which point is NOT on the line y = 5x + 1, we just need to plug each point into equation y=5x+1 to see which one point satisfies this equation.
check for (1,6)
y=5x+1
or 6=5*1+1
or 6=5+1
or 6=6
Which is TRUE.
--------
check for (2,11)
y=5x+1
or 11=5*2+1
or 11=10+1
or 11=11
Which is TRUE.
--------
check for (0,1)
y=5x+1
or 1=5*0+1
or 1=0+1
or 1=1
Which is TRUE.
--------
check for (-1,6)
y=5x+1
or 6=5*(-1)+1
or 6=-5+1
or 6=-4
Which is FALSE.
--------
Since only point (-1,6) fails to satisfy the given equation hence point (-1,6) is the final answer.
