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Gelneren [198K]
3 years ago
5

Use the substitution method to find the solution to the system of linear equations.

Mathematics
1 answer:
nataly862011 [7]3 years ago
3 0

Answer: answer is d

Step-by-step explanation: input in calculator or set both equal to y and then set them equal to each other

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PLease answer !!! Find constants $A$ and $B$ such that \[\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}\] for all
Xelga [282]

Answer:

1. (A,B) = (3,-2)

2. The values of t are: -3, -1

Step-by-step explanation:

Given

\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}

|t| = 2t + 3

Required

Solve for the unknown

Solving \frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}

Take LCM

\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{(x - 2)(x-1)}

Expand the denominator

\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - 2x + x -2}

\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - x -2}

Both denominators are equal; So, they can cancel out

x + 7 = A(x+1) + B(x-2)

Expand the expression on the right hand side

x + 7 = Ax + A + Bx - 2B

Collect and Group Like Terms

x + 7 = (Ax + Bx)  + (A - 2B)

x + 7 = (A + B)x + (A - 2B)

By Direct comparison of the left hand side with the right hand side

(A + B)x = x

A - 2B = 7

Divide both sides by x in (A + B)x = x

A + B = 1

Make A the subject of formula

A = 1 - B

Substitute 1 - B for A in A - 2B = 7

1 - B - 2B = 7

1 - 3B = 7

Subtract 1 from both sides

1 - 1 - 3B = 7 - 1

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Divide both sides by -3

B = -2

Substitute -2 for B in A = 1 - B

A = 1 - (-2)

A = 1 + 2

A = 3

Hence;

(A,B) = (3,-2)

Solving |t| = 2t + 3

Because we're dealing with an absolute function; the possible expressions that can be derived from the above expression are;

t = 2t + 3    and   -t = 2t + 3

Solving t = 2t + 3

Make t the subject of formula

t - 2t = 3

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Multiply both sides by -1

t = -3

Solving -t = 2t + 3

Make t the subject of formula

-t - 2t = 3

-3t = 3

Divide both sides by -3

t = -1

<em>Hence, the values of t are: -3, -1</em>

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