An obtuse triangle and a scalene triangle
For this case we have that by definition, the area of a square is given by:

Where:
l: It's the side of the square
We have, according to the statement data, that:

Then, the area is given by:

By definition of power properties we have to:

So:

Answer:
The area of the square is: 
Answer:

Step-by-step explanation:
Remove perfect squares from under the radicals.

_____
The applicable rules of exponents are ...
(x^a)(x^b) = x^(a+b)
√(a^2) = a . . . . . . . for a > 0
(√a)(√b) = √(ab)
Answer:
4/15 is your answer my friend
Step-by-step explanation:
Answer:
<em>Since the profit is positive, Rebotar not only broke even, they had earnings.</em>
Step-by-step explanation:
<u>Function Modeling</u>
The costs, incomes, and profits of Rebotar Inc. can be modeled by means of the appropriate function according to known conditions of the market.
It's known their fixed costs are $3,450 and their variable costs are $12 per basketball produced and sold. Thus, the total cost of Rebotar is:
C(x) = 12x + 3,450
Where x is the number of basketballs sold.
It's also known each basketball is sold at $25, thus the revenue (income) function is:
R(x) = 25x
The profit function is the difference between the costs and revenue:
P(x) = 25x - (12x + 3,450)
Operating:
P(x) = 25x - 12x - 3,450
P(x) = 13x - 3,450
If x=300 basketballs are sold, the profits are:
P(300) = 13(300) - 3,450
P(300) = 3,900 - 3,450
P(300) = 450
Since the profit is positive, Rebotar not only broke even, they had earnings.